link to problem

Description:

Given two strings text1 and text2, return the length of their longest common subsequence.

A subsequence of a string is a new string generated from the original string with some characters(can be none) deleted without changing the relative order of the remaining characters. (eg, "ace" is a subsequence of "abcde" while "aec" is not). A common subsequence of two strings is a subsequence that is common to both strings.

If there is no common subsequence, return 0.

Solution:

 class Solution:
def longestCommonSubsequence(self, text1: str, text2: str) -> int: n1 = len(text1)
n2 = len(text2) dp = [[0 for i in range(n2+1)] for j in range(n1+1)]
for i in range(n1):
for j in range(n2):
if text1[i]==text2[j]:
dp[i][j] = 1 + dp[i-1][j-1]
else:
dp[i][j] = max(dp[i-1][j], dp[i][j-1]) return dp[n1-1][n2-1]

Notes:

2-d Dynamic Programming

O(mn)

1143. Longest Common Subsequence的更多相关文章

  1. LeetCode 1143. Longest Common Subsequence

    原题链接在这里:https://leetcode.com/problems/longest-common-subsequence/ 题目: Given two strings text1 and te ...

  2. 【leetcode】1143. Longest Common Subsequence

    题目如下: Given two strings text1 and text2, return the length of their longest common subsequence. A su ...

  3. 动态规划求最长公共子序列(Longest Common Subsequence, LCS)

    1. 问题描述 子串应该比较好理解,至于什么是子序列,这里给出一个例子:有两个母串 cnblogs belong 比如序列bo, bg, lg在母串cnblogs与belong中都出现过并且出现顺序与 ...

  4. LintCode Longest Common Subsequence

    原题链接在这里:http://www.lintcode.com/en/problem/longest-common-subsequence/ 题目: Given two strings, find t ...

  5. [UCSD白板题] Longest Common Subsequence of Three Sequences

    Problem Introduction In this problem, your goal is to compute the length of a longest common subsequ ...

  6. LCS(Longest Common Subsequence 最长公共子序列)

    最长公共子序列 英文缩写为LCS(Longest Common Subsequence).其定义是,一个序列 S ,如果分别是两个或多个已知序列的子序列,且是所有符合此条件序列中最长的,则 S 称为已 ...

  7. Longest Common Subsequence

    Given two strings, find the longest common subsequence (LCS). Your code should return the length of  ...

  8. Longest Common Subsequence & Substring & prefix

    Given two strings, find the longest common subsequence (LCS). Your code should return the length of  ...

  9. Dynamic Programming | Set 4 (Longest Common Subsequence)

    首先来看什么是最长公共子序列:给定两个序列,找到两个序列中均存在的最长公共子序列的长度.子序列需要以相关的顺序呈现,但不必连续.例如,"abc", "abg", ...

随机推荐

  1. input如何上传文件

    1)绑定input[type='file']的change事件 <input @change="uploadPhoto($event)" type="file&qu ...

  2. 【译】用 `Wasmer` 进行插件开发 1

    [译]用 Wasmer 进行插件开发 1 Using Wasmer for Plugins Part 1 译文 原文链接 https://wiredforge.com/blog/wasmer-plug ...

  3. Centos7 切换 yum 源

    # yum install lrzsz修改CentOS默认yum源为mirrors.aliyun.com1.首先备份系统自带yum源配置文件/etc/yum.repos.d/CentOS-Base.r ...

  4. 【New】WoSo_我搜 正式上线

    [New]WoSo_我搜 正式上线 一站式搜索平台 聚合多种领域搜索引擎,大大提高搜索效率,使搜索更简单 地址:https://huangenet.github.io/WoSo/

  5. python SMTP发邮件

    # from email.mime.text import MIMEText from email.header import Header import smtplib # sender = 'zc ...

  6. Linux服务器上实现数据库和图片文件的定时备份

    一. 1.首先创建一个目录,用于存放备份的数据   2.在该目录下创建两个子目录一个用于存放数据库的信息,一个用于存放图片资源       3.#数据库的备份 执行下面的命令    mysqldump ...

  7. (转)JSONObject的toBean 和 fromObject

    public static void main(String[] args) { Map map=new HashMap();map.put("我","妹"); ...

  8. 树链剖分 (ZQU1607)

    这道题与模板之间,多了个确定哪个为根的操作: 这道题有技巧,并不需要真正去建立以某个节点为根的树 关于路径的操作,无论以哪个点为根,得出的答案无影响: 关于对子节点进行操作的,有几种情况, 当查询节点 ...

  9. 动态链接--运行时加载dlopen

    前面我们在编译可执行文件时,如果可执行文件要依赖某个so.必须要通过-L指定so路径,并且-l指定so名字. 而且在可执行文件运行时,要先加载so的load部分到进程地址空间. 有一种方式可以在编译时 ...

  10. 每天进步一点点------Altium Designer Rules规则详解

    对于PCB的设计, AD提供了详尽的10种不同的设计规则,这些设计规则则包括导线放置.导线布线方法.元件放置.布线规则.元件移动和信号完整性等规则.根据这些规则, Protel DXP进行自动布局和自 ...