假设你有一个很长的花坛,一部分地块种植了花,另一部分却没有。可是,花卉不能种植在相邻的地块上,它们会争夺水源,两者都会死去。

给定一个花坛(表示为一个数组包含0和1,其中0表示没种植花,1表示种植了花),和一个数 n 。能否在不打破种植规则的情况下种入 n 朵花?能则返回True,不能则返回False。

示例 1:

输入: flowerbed = [1,0,0,0,1], n = 1 输出: True

示例 2:

输入: flowerbed = [1,0,0,0,1], n = 2 输出: False

注意:

  1. 数组内已种好的花不会违反种植规则。
  2. 输入的数组长度范围为 [1, 20000]。
  3. n 是非负整数,且不会超过输入数组的大小。
class Solution {
public:
bool canPlaceFlowers(vector<int>& flowerbed, int n) {
int len = flowerbed.size();
int sum1 = 0;
int sum2 = 0;
for(int i = 0; i < len; i = i + 2)
{
if(i == 0 && flowerbed[i + 1] != 1 && flowerbed[i] != 1)
sum1++;
else if(i == len - 1 && flowerbed[i - 1] != 1 && flowerbed[i] != 1)
sum1++;
else if(flowerbed[i + 1] != 1 && flowerbed[i - 1] != 1 && flowerbed[i] != 1)
sum1++;
} for(int i = 1; i < len; i = i + 2)
{
if(flowerbed[i + 1] != 1 && flowerbed[i - 1] != 1 && flowerbed[i] != 1)
sum2++;
}
if(sum1 >= n || sum2 >= n)
return true;
return false;
}
};

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