AC日记——Sagheer and Nubian Market codeforces 812c
思路:
二分;
代码:
#include <bits/stdc++.h> using namespace std; #define maxn 1000005
#define ll long long ll n,s,ai[maxn],ci[maxn]; inline void in(ll &now)
{
char Cget=getchar();now=;
while(Cget>''||Cget<'') Cget=getchar();
while(Cget>=''&&Cget<='') now=now*+Cget-'',Cget=getchar();
} int main()
{
in(n),in(s);for(ll i=;i<=n;i++) in(ai[i]);
ll l=,r=n,ans=,ans_=,mid,pos;
for(;l<=r;)
{
mid=l+r>>;pos=;
for(ll i=;i<=n;i++) ci[i]=ai[i]+i*mid;
sort(ci+,ci+n+);for(ll i=;i<=mid;i++) pos+=ci[i];
if(pos<=s) ans=mid,ans_=pos,l=mid+;
else r=mid-;
}
printf("%lld %lld\n",ans,ans_);
return ;
}
AC日记——Sagheer and Nubian Market codeforces 812c的更多相关文章
- Sagheer and Nubian Market CodeForces - 812C (二分)
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friend ...
- CodeForce-812C Sagheer and Nubian Market(二分)
Sagheer and Nubian Market CodeForces - 812C 题意:n个货物,每个货物基础价格是ai. 当你一共购买k个货物时,每个货物的价格为a[i]+k*i. 每个货物只 ...
- Codeforces Round #417 C. Sagheer and Nubian Market
C. Sagheer and Nubian Market time limit per test 2 seconds memory limit per test 256 megabytes O ...
- Codeforces J. Sagheer and Nubian Market(二分枚举)
题目描述: Sagheer and Nubian Market time limit per test 2 seconds memory limit per test 256 megabytes in ...
- CF812C Sagheer and Nubian Market
CF812C Sagheer and Nubian Market 洛谷评测传送门 题目描述 On his trip to Luxor and Aswan, Sagheer went to a Nubi ...
- Codeforces812C Sagheer and Nubian Market 2017-06-02 20:39 153人阅读 评论(0) 收藏
C. Sagheer and Nubian Market time limit per test 2 seconds memory limit per test 256 megabytes input ...
- CodeForces - 812C Sagheer and Nubian Market 二分
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friend ...
- Codeforces Round #417 (Div. 2) C. Sagheer and Nubian Market
time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standa ...
- 【codeforces 812C】Sagheer and Nubian Market
[题目链接]:http://codeforces.com/contest/812/problem/C [题意] 给你n个物品; 你可以选购k个物品;则 每个物品有一个基础价值; 然后还有一个附加价值; ...
随机推荐
- [linux/net]策略路由实现特定主机特定路径
echo 200 silence >> /etc/iproute2/rt_tables ip rule add from 10.192.0.230 table silence ip ...
- Bigbluebutton服务执行过程及相关配置文件
BigBlueButton服务列表 BigBlueButton由许多开源的服务组成,看似很麻烦,实际上拆分开每一个服务就很简单了,组件化平台化.究竟BBB都用到了哪些开源服务?我们来列举一下,名称均带 ...
- MEF——.NET中值得体验的精妙设计
摘要:.NET 是 Microsoft XML Web services 平台.MEF是.NET Framework 4.0一个重要的库,Visual Studio 2010 Code Editor的 ...
- Beagleboneblack的MLO文件干了些啥
Beagleboneblack在启动linux之前还有三个启动阶段: ROM code --> MLO --> u-boot --> kernel 先看看ROM code干了 ...
- 数学:拓展BSGS
当C不是素数的时候,之前介绍的BSGS就行不通了,需要用到拓展BSGS算法 方法转自https://blog.csdn.net/zzkksunboy/article/details/73162229 ...
- vijos 1004 伊甸园日历游戏 博弈+打表找规律
描述 Adam和Eve玩一个游戏,他们先从1900.1.1到2001.11.4这个日期之间随意抽取一个日期出来.然后他们轮流对这个日期进行操作: 1 : 把日期的天数加1,例如1900.1.1变到19 ...
- PHP扩展--Yaf框架安装
安装/配置 编译安装 wge thttp://pecl.php.net/get/yaf-2.3.5.tgz tar -zxvfyaf-2.3.5.tgz cd yaf-2.3.5/ cd extens ...
- Spring boot 集成Dubbox(山东数漫江湖)
前言 因为工作原因,需要在项目中集成dubbo,所以去查询dubbo相关文档,发现dubbo目前已经不更新了,所以把目光投向了dubbox,dubbox是当当网基于dubbo二次开发的一个项目,dub ...
- HDU 1002 A + B Problem II (大数加法)
题目链接 Problem Description I have a very simple problem for you. Given two integers A and B, your job ...
- 24、redis中的sentinel的作用?
redis中的sentinel的作用? Redis-Sentinel是Redis官方推荐的高可用性(HA)解决方案,当用Redis做Master-slave的高可用方案时,假如master宕机了,Re ...