用sliding window的方法,之前还有个k不同元素好像也是类似的思路。有时间可以去复习下。

https://leetcode.com/problems/longest-repeating-character-replacement/

// sliding window

public class Solution {
public int characterReplacement(String s, int k) { int[] count = new int[26]; int maxch = -1; // the char with max count in current substr
int max = 0; // the max count for single char in current substr
int len = 0; // current substr length
int ret = 0; // final result for (int i=0; i<s.length(); i++) {
int tmp = s.charAt(i) - 'A';
count[tmp]++;
len++; if (maxch == tmp) {
max++;
}
else {
if (count[tmp] > max) {
max = count[tmp];
maxch = tmp;
}
} if (len - max <= k) {
if (len > ret) {
ret = len;
}
} while (len - max > k) {
int newTmp = s.charAt(i-len+1) - 'A';
count[newTmp]--;
len--;
if (maxch == newTmp) {
max--;
for (int j=0; j<26; j++) {
if (count[j] > max) {
max = count[j];
maxch = j;
}
}
}
}
}
return ret;
}
}

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