5. Longest Palindromic Substring

Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000.

Example:

Input: "babad"

Output: "bab"

Note: "aba" is also a valid answer.

Example:

Input: "cbbd"

Output: "bb"
 class Solution:
def solve(self,s,l,r):
while r<len(s) and l>= and s[l]==s[r]:
l-=
r+=
return s[l+:r]
def longestPalindrome(self,s):
if len(s) == :
return
max_string=''
for i in range(len(s)):
#奇数长度回文串如ababa
tmp=self.solve(s,i,i)
if len(tmp)>len(max_string):
max_string=tmp
#偶数回文串如abba tmp=self.solve(s,i,i+)
if len(tmp)>len(max_string):
max_string=tmp return max_string

Code

 def solve(s,l,r):
while r<len(s) and l>= and s[l]==s[r]:
l-=
r+=
return s[l+:r]
def longestPalindrome(s):
if len(s) == :
return
max_string=''
for i in range(len(s)):
#奇数长度回文串如ababa
tmp=solve(s,i,i)
if len(tmp)>len(max_string):
max_string=tmp
#偶数回文串如abba tmp=solve(s,i,i+)
if len(tmp)>len(max_string):
max_string=tmp return max_string print(longestPalindrome('ababa'))

Debug Code

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