ZOJ3704 I am Nexus Master! 2017-04-06 23:36 56人阅读 评论(0) 收藏
I am Nexus Master!
Time Limit: 2 Seconds Memory Limit: 65536 KB
NexusHD.org is a popular PT (Private Tracker) site in Zhejiang University aiming to provide high quality stuff. In order to encourage users to unload more stuff, the administrators
make the following rules to classified users into different classes by the uploaded/downloaded ratio and register time. Users with higher ranks will enjoy more privileges while users in the lowest class(Peasant) would be banned if they couldn't promote from
this class for a certain period.
The detail rules are as follows, referring to the FAQ page from NexusHD.org with some modification.
Class Title |
Description |
|
| Peasant | User would be demoted to this class under any of the following circumstances: 1.Downloaded at least 50 GB and with ratio below 0.4 2.Downloaded at least 100 GB and with ratio below 0.5 3.Downloaded at least 200 GB and with ratio below 0.6 4.Downloaded at least 400 GB and with ratio below 0.7 5.Downloaded at least 800 GB and with ratio below 0.8 |
|
| User | Default class. | |
| Power_User | Been a member for at least 4 weeks, have downloaded at least 50GB and have a ratio at or above 1.05, and will be demoted from this status if ratio drops below 0.95. | |
| Elite_User | Been a member for at least 8 weeks, have downloaded at least 120GB and have a ratio at or above 1.55, and will be demoted from this status if ratio drops below 1.45. | |
| Crazy_User | Been a member for at least 15 weeks, have downloaded at least 300GB and have a ratio at or above 2.05, and will be demoted from this status if ratio drops below 1.95. | |
| Insane_User | Been a member for at least 25 weeks, have downloaded at least 500GB and have a ratio at or above 2.55, and will be demoted from this status if ratio drops below 2.45. | |
| Veteran_User | Been a member for at least 40 weeks, have downloaded at least 750GB and have a ratio at or above 3.05, and will be demoted from this status if ratio drops below 2.95. | |
| Extreme_User | Been a member for at least 60 weeks, have downloaded at least 1TB and have a ratio at or above 3.55, and will be demoted from this status if ratio drops below 3.45. | |
| Ultimate_User | Been a member for at least 80 weeks, have downloaded at least 1.5TB and have a ratio at or above 4.05, and will be demoted from this status if ratio drops below 3.95. | |
| Nexus_Master | Been a member for at least 100 weeks, have downloaded at least 3TB and have a ratio at or above 4.55, and will be demoted from this status if ratio drops below 4.45. |
I am Nexus_Master, the highest class. And you, a young programmer, are asked to implement a small procedure to decide which class the user belongs to according to the above rules.
And this procedure will be invoked by main loop from time to time to modify the title of users. Maybe you will be gift a title after finishing this task.
The procedure would take four parameters of a single user as input: current class title, registration time, total downloaded, and total uploaded, and return a string as the new class
title of the user.
Input
The first line contains a single integer T (T ≤ 10000), indicating there are T cases in total.
There will be 4 parameters in each of the following T lines, as mentioned in the previous description :
- Current class title: one of the 10 titles in the detail rules;
- Register time: an non-negative integer representing the time span from the register moment to now, in unit of weeks;
- Total downloaded: a non-negative decimal number with 2 decimal digits after the decimal point, in unit of GBs;
- Total uploaded: a non-negative decimal number with 2 decimal digits after the decimal point, in unit of GBs.
Parameters are separated by a single space. All numerical parameters would not be greater than 106.
Outout
For each case, output the new class title of the user in a single line. Note that the tile should be one of the 10 titles in the above table.
Sample Input
3
Crazy_User 15 800.00 639.99
Veteran_User 45 1000.00 3000.00
Insane_User 45 1000.00 3000.00
Sample Output
Peasant
Veteran_User
Insane_User
Hint
——————————————————————————————————————————————————————
题目的意思是一个论坛有各种等级,给出当前等级和注册时间和下载量和上传量
求变动之后的等级,各种等级的关系如题目所给
#include <iostream>
#include <cstdio>
#include <string>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <queue>
#include <vector>
#include <set>
#include <stack>
#include <map>
#include <cctype>
#include <sstream>
#include <climits>
#include <unordered_map> using namespace std; #define LL long long
const int INF=0x3f3f3f3f;
map<string,int>mp; string ans[10]; void init()
{
mp["User"]=1;
mp["Power_User"]=2;
mp["Elite_User"]=3;
mp["Crazy_User"]=4;
mp["Insane_User"]=5;
mp["Veteran_User"]=6;
mp["Extreme_User"]=7;
mp["Ultimate_User"]=8;
mp["Nexus_Master"]=9;
ans[0]="Peasant";
ans[1]="User";
ans[2]="Power_User";
ans[3]="Elite_User";
ans[4]="Crazy_User";
ans[5]="Insane_User";
ans[6]="Veteran_User";
ans[7]="Extreme_User";
ans[8]="Ultimate_User";
ans[9]="Nexus_Master"; } int slove(int lv,double t,double d,double u)
{
double r=u/d;
int ran=1;
if(d>=50&&r<0.4) return 0;
if(d>=100&&r<0.5) return 0;
if(d>=200&&r<0.6) return 0;
if(d>=400&&r<0.7) return 0;
if(d>=800&&r<0.8) return 0;
if(t>=4&&d>=50&&r>=1.05) ran=2;
if(t>=8&&d>=120&&r>=1.55) ran=3;
if(t>=15&&d>=300&&r>=2.05) ran=4;
if(t>=25&&d>=500&&r>=2.55) ran=5;
if(t>=40&&d>=750&&r>=3.05) ran=6;
if(t>=60&&d>=1024&&r>=3.55) ran=7;
if(t>=80&&d>=1024*1.5&&r>=4.05) ran=8;
if(t>=100&&d>=1024*3&&r>=4.55) ran=9; if(lv==9&&r<4.45) lv--;
if(lv==8&&r<3.95) lv--;
if(lv==7&&r<3.45) lv--;
if(lv==6&&r<2.95) lv--;
if(lv==5&&r<2.45) lv--;
if(lv==4&&r<1.95) lv--;
if(lv==3&&r<1.45) lv--;
if(lv==2&&r<0.95) lv--;
return max(lv,ran);
} int main()
{
string s;
double time,u,d;
int T;
init();
scanf("%d",&T);
while(T--)
{
cin>>s>>time>>d>>u;
cout<<ans[slove(mp[s],time,d,u)]<<endl;
} return 0;
}
ZOJ3704 I am Nexus Master! 2017-04-06 23:36 56人阅读 评论(0) 收藏的更多相关文章
- Adding a WebPart to a SharePoint 2013 Master Page 分类: Sharepoint 2015-07-08 01:03 7人阅读 评论(0) 收藏
On SharePoint 2013 you can not add the Web Parts to the master page the same way of 2010. Please use ...
- Dungeon Master 分类: 搜索 POJ 2015-08-09 14:25 4人阅读 评论(0) 收藏
Dungeon Master Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 20995 Accepted: 8150 Descr ...
- cubieboard变身AP 分类: ubuntu cubieboard 2014-11-25 14:04 277人阅读 评论(0) 收藏
加载bcmdhd模块:# modprobe bcmdhd 如果你希望开启 AP 模式,那么:# modprobe bcmdhd op_mode=2 在/etc/modules文件内添加bcmdhd o ...
- HDU1551&&HDU1064 Cable master 2017-05-11 17:50 38人阅读 评论(0) 收藏
Cable master Time Limit: ...
- HDU6029 Graph Theory 2017-05-07 19:04 40人阅读 评论(0) 收藏
Graph Theory Time Limit: 2000/1000 M ...
- 2014/11/06 Oracle触发器初步 2014-11-06 09:03 49人阅读 评论(0) 收藏
触发器我就不多解释了,保证数据的完整性的神器,嗯..也是减少程序员工作托管给数据库操作的好帮手.就不讲一些大道理了.通俗点,我们对数据库的操作,无非就是增 删 改 查. 触发器就是在删,改,增的时候( ...
- hdu 1159, LCS, dynamic programming, recursive backtrack vs iterative backtrack vs incremental, C++ 分类: hdoj 2015-07-10 04:14 112人阅读 评论(0) 收藏
thanks prof. Abhiram Ranade for his vedio on Longest Common Subsequence 's back track search view in ...
- NPOI 通用导出数据到Excel 分类: C# Helper 2014-11-04 16:06 246人阅读 评论(0) 收藏
应用场景: 在项目中,经常遇到将数据库数据导出到Excel,针对这种情况做了个程序封装.工作原理:利用NPOI将SQL语句查询出的DataTable数据导出到Excel,所见即所得. 程序界面: ...
- cloud theory is a failure? 分类: Cloud Computing 2013-12-26 06:52 269人阅读 评论(0) 收藏
since LTE came out, with thin client cloud computing and broadband communication clouding 不攻自破了.but ...
随机推荐
- 显示列表控件(引用SourceGrid)
using System; using System.Collections.Generic; using System.ComponentModel; using System.Drawing; u ...
- Python笔试题&面试题总结
黑色加粗的是笔试题,蓝色是面试题 1.什么是GIL 2.Python中的@staticmethod和@classmethod的区别 (**) 3.Python里面如何拷贝一个对象,并解析深浅拷贝 4. ...
- [题解] [NOIP2008] 双栈排序——关系的冲突至图论解法
Problem 题目描述 Tom最近在研究一个有趣的排序问题.如图所示,通过2个栈S1和S2,Tom希望借助以下4种操作实现将输入序列升序排序. 操作a 如果输入序列不为空,将第一个元素压入栈S1 操 ...
- Excel图片调整大小
Excel图片调整大小 Sub 图片调整合适大小() ' Debug.Print ActiveWorkbook.Name 图片显示比例 = 0.9 '1为顶满单元格 Dim wb As Workboo ...
- bzoj4891: [Tjoi2017]龙舟
求$\frac{b_1b_2b_3...b_m}{a_1a_2a_3...a_m}\%M$ M<=1e18,m<=100000,数据组数<=50 用pollard-rho分解M的质因 ...
- post参数的方法 json data 和特别的传参
json格式传参: 那么久使用json的方式传参: json=payload data格式传参: 其他方式传参: 在webFormes里 value 的值不是普通的字符 要把value值先序列化在放入 ...
- 设置putty标题栏显示固定信息
设置好后,登录服务器后,发现标题栏又显示root@sit:/opt/ihome,没有显示成我设置的title内容.原因是: 在Terminal->Features中一定要勾选Disable re ...
- javascript中不存在块级作用域,所以要小心使用在块级作用域中的函数声明所带来的作用域混乱.
在javascript中函数的作用域是一个非常重要的概念. javascript中是没有块级作用域,但是有函数作用域的概念. 我们在开发的过程中,经常会遇到这样的问题, 某个函数我暂时不需要,不想声明 ...
- 【Codeforces】Codeforces Round #492 (Div. 2) (Contest 996)
题目 传送门:QWQ A:A - Hit the Lottery 分析: 大水题 模拟 代码: #include <bits/stdc++.h> using namespace std; ...
- setAttribute第三个参数
object.setAttribute(sName, vValue [, iFlags]) sName参数应是Dom属性而非html中的属性.Dom中Html专有的接口属性应该以小写字母开头,如果属性 ...