A1147. Heaps
In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))
Your job is to tell if a given complete binary tree is a heap.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers: M (≤ 100), the number of trees to be tested; and N (1 < N ≤ 1,000), the number of keys in each tree, respectively. Then M lines follow, each contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, print in a line Max Heap if it is a max heap, or Min Heap for a min heap, or Not Heap if it is not a heap at all. Then in the next line print the tree's postorder traversal sequence. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line.
Sample Input:
3 8
98 72 86 60 65 12 23 50
8 38 25 58 52 82 70 60
10 28 15 12 34 9 8 56
Sample Output:
Max Heap
50 60 65 72 12 23 86 98
Min Heap
60 58 52 38 82 70 25 8
Not Heap
56 12 34 28 9 8 15 10
#include<iostream>
#include<cstdio>
using namespace std;
int N, M, tree[];
int isMaxheap(){
for(int k = N / ; k >= ; k--){
int max;
if(*k + <= N && tree[*k+] > tree[*k]){
max = tree[*k + ];
}else{
max = tree[*k];
}
if(tree[k] < max)
return ;
}
return ;
}
int isMinheap(){
for(int k = N / ; k >= ; k--){
int min;
if(*k+ <= N && tree[*k+] < tree[*k]){
min = tree[*k+];
}else min = tree[*k];
if(tree[k] > min)
return ;
}
return ;
}
int cnt = ;
void postOrder(int root){
if(root > N)
return;
postOrder(root*);
postOrder(root* + );
cnt++;
if(cnt == N)
printf("%d\n", tree[root]);
else printf("%d ", tree[root]);
}
int main(){
scanf("%d%d", &M, &N);
for(int i = ; i < M; i++){
for(int i = ; i <= N; i++){
scanf("%d", &tree[i]);
}
if(isMaxheap()){
printf("Max Heap\n");
}else if(isMinheap()){
printf("Min Heap\n");
}else{
printf("Not Heap\n");
}
cnt = ;
postOrder();
}
cin >> N;
return ;
}
总结:
1、题意:检查每个给出的序列是否是一个大根堆或者小根堆。
A1147. Heaps的更多相关文章
- PAT A1147 Heaps (30 分)——完全二叉树,层序遍历,后序遍历
In computer science, a heap is a specialized tree-based data structure that satisfies the heap prope ...
- PAT_A1147#Heaps
Source: PAT A1147 Heaps (30 分) Description: In computer science, a heap is a specialized tree-based ...
- PAT (Advanced Level) Practice(更新中)
Source: PAT (Advanced Level) Practice Reference: [1]胡凡,曾磊.算法笔记[M].机械工业出版社.2016.7 Outline: 基础数据结构: 线性 ...
- PAT甲级题解分类byZlc
专题一 字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d& ...
- CodeForces 353B Two Heaps
B. Two Heaps Valera has 2·n cubes, each cube contains an integer from 10 to 99. He arbitrarily cho ...
- DSP\BIOS调试Heaps are enabled,but not set correctly
转自:http://blog.sina.com.cn/s/blog_735f291001015t9i.html Heaps are enabled, but the segment for DSP/B ...
- CSU 1616: Heaps(区间DP)
题目链接:http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1616 1616: Heaps Time Limit: 2 Sec Memory Lim ...
- Codeforces Round #300 F - A Heap of Heaps (树状数组 OR 差分)
F. A Heap of Heaps time limit per test 3 seconds memory limit per test 512 megabytes input standard ...
- Heaps(Contest2080 - 湖南多校对抗赛(2015.05.10)(国防科大学校赛决赛-Semilive)+scu1616)
Problem H: Heaps Time Limit: 2 Sec Memory Limit: 128 MBSubmit: 48 Solved: 9[Submit][Status][Web Bo ...
随机推荐
- mac下virtualbox中centos6.5虚拟机实现全屏和调整分辨率
在visualbox里安装好centos后,发现不能分辨率与原屏幕不一致,很多解决方法是:安装增强包.可是安装增强包后依然达不到效果. 究其原因,原来因为没有安装显卡驱动导致安装了增强包后无法实现分辨 ...
- Spring Boot(1)——开发你的第一款Spring Boot应用(Edition1)
Spring Boot(1)——开发你的第一款Spring Boot应用(Edition1) 准备工作: java:java 8 或者 java 9: Spring框架:5.0.8.RELEASE或以 ...
- mycat - 全局序列
解决主键冲突问题:例如id自增的order表,如果分布式情况下不处理的话,当每个表的第一条数据id都是1. 怎么确保id唯一呢? 解决办法: 1.本地文件(不推荐) 2.数据库方式(推荐) 3.时间戳 ...
- 莫烦scikit-learn学习自修第三天【通用训练模型】
1. 代码实战 #!/usr/bin/env python #!_*_ coding:UTF-8 _*_ import numpy as np from sklearn import datasets ...
- 剖析插件 DataTable 自定义列表列get请求如何书写传递的参数
重点代码Demo 已用 斜体标注 后端flask: @task_mgm.route('/taskinfo_editID=<int:num>', methods=['GET', 'POST' ...
- css 浮动问题 display显示 和 光标设置cursor
<!DOCTYPE html><html> <head> <meta charset="UTF-8"> <title>浮 ...
- 【NLP】How to Generate Embeddings?
How to represent words. 0 . Native represtation: one-hot vectors Demision: |all words| (too large an ...
- fiddler软件测试——Fiddler抓取https设置详解(图文)
强烈推荐(原创亲测)!!!Fiddler抓取https设置详解(图文)转 本文主要说明了自己在设置fiddler抓取https过程中所遇到的问题及解决步骤,特别是fiddler在设置证书的环节遇到的各 ...
- BZOJ1004[HNOI2008]Cards——polya定理+背包
题目描述 小春现在很清闲,面对书桌上的N张牌,他决定给每张染色,目前小春只有3种颜色:红色,蓝色,绿色.他询问Sun有多少种染色方案,Sun很快就给出了答案.进一步,小春要求染出Sr张红色,Sb张蓝色 ...
- Django auth认证系统
Django自带的用户认证 我们在开发一个网站的时候,无可避免的需要设计实现网站的用户系统.此时我们需要实现包括用户注册.用户登录.用户认证.注销.修改密码等功能,这还真是个麻烦的事情呢. Djang ...