leetcode:Count and Say【Python版】

一次AC

字符串就是：count+char

 class Solution:
     # @return a string
     def countAndSay(self, n):
         str = ""
         for i in range(n-1):
             tmp = str
             str = ""
             c = tmp[0]
             cnt = 1
             for j in range(1,len(tmp)):
                 if tmp[j] == tmp[j-1]:
                     cnt += 1
                 else:
                     str += ("%d"%cnt + tmp[j-1])
                     cnt = 1
             str += ("%d"%cnt + tmp[len(tmp)-1])
         return str