LeetCode 7 Reverse Integer int:2147483647-2147483648 难度:2

https://leetcode.com/problems/reverse-integer/

class Solution {
public:
    int inf = ~0u >> 1;
    int reverse(int x) {
        if(x == 0)return 0;
        long long tx = x;
        long long ans = 0;
        for(int i = 0;tx;i++){
            ans = ans * 10 + tx % 10;
            tx /= 10;
        }
        return int(ans) == ans?ans:0;
    }
};