DFS+模拟 ZOJ 3861 Valid Pattern Lock
/*
题意:手机划屏解锁,一笔连通所有数字,输出所有可能的路径;
DFS:全排列 + ok () 判断函数,去除一些不可能连通的点:)
*/
#include <cstdio>
#include <iostream>
#include <algorithm>
#include <cstring>
#include <string>
#include <map>
#include <cmath>
#include <vector>
#include <set>
#include <queue>
using namespace std; const int MAXN = ;
const int INF = 0x3f3f3f3f;
int a[], ans[];
int n, x;
int vis[];
int res[MAXN][];
int flag[]; bool ok(void)
{
memset (flag, , sizeof (flag)); int i;
for (i=; i<=n-; i++) //小细节决定成败
{
flag[ans[i]] = ;
if((ans[i] == && ans[i+] == && flag[] == )|| (ans[i] == && ans[i+] == && flag[] == ) ||
(ans[i] == && ans[i+] == && flag[] == )|| (ans[i] == && ans[i+] == && flag[] == ) ||
(ans[i] == && ans[i+] == && flag[] == )|| (ans[i] == && ans[i+] == && flag[] == ) ||
(ans[i] == && ans[i+] == && flag[] == )|| (ans[i] == && ans[i+] == && flag[] == ) ||
(ans[i] == && ans[i+] == && flag[] == )|| (ans[i] == && ans[i+] == && flag[] == ) ||
(ans[i] == && ans[i+] == && flag[] == )|| (ans[i] == && ans[i+] == && flag[] == ) ||
(ans[i] == && ans[i+] == && flag[] == )|| (ans[i] == && ans[i+] == && flag[] == ) ||
(ans[i] == && ans[i+] == && flag[] == )|| (ans[i] == && ans[i+] == && flag[] == ) )
return ; }
if(i == n)
return true;
} void DFS(int cnt)
{
if (cnt == n + )
{
if (ok ())
{
x++;
for (int i=; i<=n; i++)
{
res[x][i] = ans[i];
}
} return ;
} for (int i=; i<=n; i++)
{
if (!vis[a[i]])
{
ans[cnt] = a[i];
vis[a[i]] = ;
DFS (cnt + );
vis[a[i]] = ;
}
}
} int main(void) //ZOJ 3861 Valid Pattern Lock
{
//freopen ("B.in", "r", stdin); int t;
scanf ("%d", &t);
while (t--)
{
//memset (res, -1, sizeof (res)); //这句话没写导致WA n次!!!
memset (vis, , sizeof (vis)); //注意初始化,上面的作用已在ok () Debug 出来了
scanf ("%d", &n); for (int i=; i<=n; ++i) scanf ("%d", &a[i]);
sort(a+,a+n+);
x = ;
DFS (); printf ("%d\n", x);
for (int i=; i<=x; ++i)
{
for (int j=; j<=n; ++j)
{
printf ("%d%c", res[i][j], (j==n) ? '\n' : ' ');
}
} } return ;
}
DFS+模拟 ZOJ 3861 Valid Pattern Lock的更多相关文章
- ZOJ 3861 - Valid Pattern Lock
3861 - Valid Pattern Lock Time Limit:2000MS Memory Limit:65536KB 64bit IO Format:%lld & ...
- ACM学习历程—ZOJ 3861 Valid Pattern Lock(dfs)
Description Pattern lock security is generally used in Android handsets instead of a password. The p ...
- 浙江大学2015年校赛B题 ZOJ 3861 Valid Pattern Lock
这道题目是队友写的,貌似是用暴力枚举出来. 题意:给出一组数,要求这组数在解锁的界面可能的滑动序列. 思路:按照是否能够直接到达建图,如1可以直接到2,但是1不能直接到3,因为中间必须经过一个2. 要 ...
- ZOJ - 3861 Valid Pattern Lock 【全排列】
题目链接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3861 思路 先生成全排列,然后判断哪些情况不符合的,剔除就好了 ...
- ZOJ Problem Set - 3861 Valid Pattern Lock(dfs)
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3861 这道题当时没做出来,后来经过队友提醒才做出来. 3*3的九宫格,给你 ...
- Valid Pattern Lock(dfs + 暴力)
Valid Pattern Lock Time Limit: 2 Seconds Memory Limit: 65536 KB Pattern lock security is genera ...
- zoj 3861(dfs)
Valid Pattern Lock Time Limit: 2 Seconds Memory Limit: 65536 KB Pattern lock security is genera ...
- Bypass pattern lock on Sony Xperia Z2 and backup all data
Yesterday she came to me with a Sony Xperia Z2 D6503. Guess what? She forgot the pattern so she coul ...
- Deal with Android phones with pattern lock on
Yesterday my colleague asked me for help...She has two android phones , one is hTC and the other is ...
随机推荐
- dedecms如何随机调用指定分类下的文章到网站首页
dedecms是全静态的,有时会因为其他事情好几天没写文章推荐到首页,那样对se不是很友好.原本ytkah是想在网站首页上半部分调用几篇id从200到500的文章随机展示的,这样每次更新首页给se的赶 ...
- The Pilots Brothers' refrigerator(dfs)
The Pilots Brothers' refrigerator Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 19718 ...
- IOS 使用横屏
http://lizhuang.iteye.com/blog/1684881 在iPad应用开发时如何让设备只支持横屏(landscape)模式,我做了多次尝试,并没有发现比较简捷的设置方法.我尝试了 ...
- Hibernate执行原生SQL返回List<Map>类型结果集
我是学java出身的,web是我主要一块: 在做项目的时候最让人别扭的就是hibernate查询大都是查询出List<T>(T指代对应实体类)类型 如果这时候我用的联合查询,那么返回都就是 ...
- Linux rpm安装问题解决
1.安装时提示:warning: *.rpm: Header V3 RSA/SHA256 Signature, keykey ID c105b9de: NOKEY 解决的方法就是在rpm 语句后面加上 ...
- ubuntu14.04安装chrome
到https://www.google.com/chrome/browser/desktop/index.html可下载指定版本的deb文件. 32bit: wget https://dl.googl ...
- 【Django】Django 直接执行原始SQL 如何防止SQL注入 ?
代码示例: #错误--不要直接格式化字符串 query = 'SELECT * FROM myapp_person WHERE last_name = %s' % lname Person.objec ...
- 【leetcode】String to Integer (atoi)
String to Integer (atoi) Implement atoi to convert a string to an integer. Hint: Carefully consider ...
- Java for LeetCode 187 Repeated DNA Sequences
All DNA is composed of a series of nucleotides abbreviated as A, C, G, and T, for example: "ACG ...
- 10.python之socket和socketserver
1.socket介绍 socket的英文原义是"孔"或"插座".作为BSD UNIX的进程通信机制,取后一种意思.通常也 称作"套接字",用 ...