[HihoCoder] Highway 高速公路问题
Description
In the city, there is a one-way straight highway starts from the northern end, traverses the whole city southward, and finishes at the southern end. Due to some financial difficulties, there is only one lane on this highway, which means that overtaking other cars in front is impossible.
The highway is quite busy. Lots of different cars are running on it every day. For each car, it is running on the highway at the point which X km far from the northern end in Minute 0, and will leave at the point which Y km far from the northern end. Each car also has a speed limit L km/min. During the whole trip on the highway, each car should run as fast as possible without exceeding its speed limit or overtaking other cars in front. In addition, no two or more cars will be at the same point at Minute 0. Cars can be regarded as points and the distance between two cars can be infinitely small.
Given the information of N cars, please calculate the leaving time for each car.
Input
The first line contains one integer N. 2 <= N <= 1000.
Then follows N line. Each line contains three integers X, Y and L, showing the information of this car. 0 <= X < Y <= 1000000, 0 < L <= 10.
Output
Output N real numbers, one per line -- the leaving time (in minute) of each car, preserving the input order of cars. Your answers should be rounded to 2 digits after the decimal point and the output must contain exactly 2 digits after the decimal point.
Sample Input
3
3 5 1
1 4 2
0 8 3
Sample Output
2.00
1.50
3.00
参考资料:
http://hihocoder.com/discuss/question/2533
[HihoCoder] Highway 高速公路问题的更多相关文章
- 【IOI 2018】Highway 高速公路收费
这是一道极好的图论题,虽然我一开始只会做$18$分,后来会做$51$分,看着题解想了好久才会做(吐槽官方题解:永远只有一句话),但这的确是一道好题,值得思考,也能启发思维. 如果要讲这道题,还是要从部 ...
- UVA 1615 Highway 高速公路 (区间选点)
题意:在一条线段上选出尽量少的点,使得和所有给出的n个点距离不超过D. 分别计算出每个点在线段的满足条件的区间,然后就转化成了区间选点的问题了,按照右端点排序,相同时按照左端点排序,按照之前的排序一定 ...
- CNN卷积神经网络_深度残差网络 ResNet——解决神经网络过深反而引起误差增加的根本问题,Highway NetWork 则允许保留一定比例的原始输入 x。(这种思想在inception模型也有,例如卷积是concat并行,而不是串行)这样前面一层的信息,有一定比例可以不经过矩阵乘法和非线性变换,直接传输到下一层,仿佛一条信息高速公路,因此得名Highway Network
from:https://blog.csdn.net/diamonjoy_zone/article/details/70904212 环境:Win8.1 TensorFlow1.0.1 软件:Anac ...
- 高速公路(Highway,ACM/ICPC SEERC 2005,UVa1615)
I think: #include <stdio.h> #include <stdlib.h> #include <string.h> #include <m ...
- UVA - 1615 Highway(高速公路)(贪心+区间选点)
题意:给定平面上n(n<=105)个点和一个值D,要求在x轴上选出尽量少的点,使得对于给定的每个点,都有一个选出的点离它的欧几里德距离不超过D. 分析: 1.根据D可以算出每个点在x轴上的可选区 ...
- 【论文笔记】Training Very Deep Networks - Highway Networks
目标: 怎么训练很深的神经网络 然而过深的神经网络会造成各种问题,梯度消失之类的,导致很难训练 作者利用了类似LSTM的方法,通过增加gate来控制transform前和transform后的数据的比 ...
- Highway Networks(高速路神经网络)
Rupesh Kumar Srivastava (邮箱:RUPESH@IDSIA.CH)Klaus Greff (邮箱:KLAUS@IDSIA.CH)J¨ urgen Schmidhuber (邮箱: ...
- hihocoder -1121-二分图的判定
hihocoder -1121-二分图的判定 1121 : 二分图一•二分图判定 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 大家好,我是小Hi和小Ho的小伙伴Net ...
- Hihocoder 太阁最新面经算法竞赛18
Hihocoder 太阁最新面经算法竞赛18 source: https://hihocoder.com/contest/hihointerview27/problems 题目1 : Big Plus ...
随机推荐
- CSS本页写样式
<style type="text/css">p{ color:#ff0000; font-size:24px; font-family:"隶书"; ...
- #define 的一些用法 以及 迭代器的 [] 与 find()函数的区别
#include "stdafx.h" #include <map> #include <string> #include <iostream> ...
- codeforces B. New Year Present 解题报告
题目链接:http://codeforces.com/contest/379/problem/B 题目意思:给定一个有n个钱包的序列,其中第i个钱包需要投入ai个钱币,需要编写一个程序,使得在对第i个 ...
- 51nod 1264 线段相交
题目:传送门. 题意:给两条线段,有一个公共点或有部分重合认为相交,问他们是否相交. 题解:这属于非规范相交的情况,模板题. #include <iostream> #include &l ...
- 小吃(codevs 3231)
3231 小吃 时间限制: 1 s 空间限制: 16000 KB 题目等级 : 黄金 Gold 题解 查看运行结果 题目描述 Description 这里简直是吃货的天堂,小吃太多了. ...
- cf158B(水题)
题意:1辆出租车可以坐4人,已知k组人每组ki(ki<=4)人去坐车,要求同组人坐同一辆车,求最少需多少辆车.. 4人组的单独算,1人组和3人组一起,如1多余再将1和2匹配即可.... 代码如下 ...
- 一个可能有用的封闭PGSQL操作的PYTHON函数
URL: http://www.linuxyw.com/517.html 一般操作: import psycopg2 连接数据库 conn = psycopg2.connect(database=db ...
- ASP.NET 数据库访问通用工具
在工作中,有很多项目已上线后,很多项目的数据库服务器都不会对外开放的,外网想直接访问客户数据库服务器时,可能会出现困难. 这时就需要一个可以查询,更新数据库操作的页面了: 本来用sql语句直接操作数据 ...
- poj 1236 scc强连通分量
分析部分摘自:http://www.cnblogs.com/kuangbin/archive/2011/08/07/2130277.html 强连通分量缩点求入度为0的个数和出度为0的分量个数 题目大 ...
- Syncfusion的社区许可及免费电子书和白皮书
今晚由于要忙于其他事情,就简单的给大家推荐一个第三方组件库.特别注明:这是我义务为这家公司打广告.毕竟我从他们公司收获了很多知识. Syncfusion是一家微软生态下的第三方组件/控件供应商,算是后 ...