[工具类]泛型集合转换为DataTable

写在前面

在实际项目中，用到了将集合转换为DataTable，就试着封装了一个方法，记录一下。

代码

using System;
using System.Collections.Generic;
using System.Data;
using System.Linq;
using System.Reflection;
using System.Text;
using System.Threading.Tasks;

namespace Wolfy.List2DataTable
{
    class Program
    {
        static void Main(string[] args)
        {
            List<Person> lst = new List<Person>()
            {
                new Person(){ ID=, Gender=false, Name="wolfy1"},
                 new Person(){ ID=, Gender=false, Name="wolfy2"},
                  new Person(){ ID=, Gender=false, Name="wolfy3"},
                   new Person(){ ID=, Gender=false, Name="wolfy4"},
                    new Person(){ ID=, Gender=false, Name="wolfy5"},
            };
            DataTable dt = List2DataTable<Person>(lst);
            Console.WriteLine("转换结束");
            Console.Read();
        }
        /// <summary>
        /// 将泛型集合转换为datatable
        /// </summary>
        /// <typeparam name="TEntity"></typeparam>
        /// <param name="entities"></param>
        /// <returns></returns>
        static DataTable List2DataTable<TEntity>(List<TEntity> entities)
        {
            if (entities == null)
            {
                throw new ArgumentNullException("转换的集合为空");
            }
            Type type = typeof(TEntity);
            PropertyInfo[] properties = type.GetProperties();
            DataTable dt = new DataTable(type.Name);
            foreach (var item in properties)
            {
                dt.Columns.Add(new DataColumn(item.Name) { DataType = item.PropertyType });
            }
            foreach (var item in entities)
            {
                DataRow row = dt.NewRow();
                foreach (var property in properties)
                {
                    row[property.Name] = property.GetValue(item);
                }
                dt.Rows.Add(row);
            }
            return dt;
        }
    }
    public class Person
    {
        public int ID { set; get; }
        public string Name { set; get; }
        public bool Gender { set; get; }
    }
}

测试结果：