hdu 4952 暴力

http://acm.hdu.edu.cn/showproblem.php?pid=4952

给定x，k，i从1到k，每次a[i]要是i的倍数，并且a[i]大于等于a[i-1],x为a0

递推到下一个a==之前的a即可跳出循环

#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <cstring>
#include <string>
#include <queue>
#include <map>
#include <iostream>
#include <algorithm>
using namespace std;
#define RD(x) scanf("%d",&x)
#define RD2(x,y) scanf("%I64d%I64d",&x,&y)
#define RD3(x,y,z) scanf("%d%d%d",&x,&y,&z)
#define clr0(x) memset(x,0,sizeof(x))
typedef long long LL;
const int modo = 1e9 + 7;
#define eps 1e-9

int main () {
    int cas = 1;
    LL n, k;

    while (~RD2(n,k) && n + k) {
        LL x = n, a = n;

        for (LL i = 2; i <= k; i++) {
            LL tmp = (x - 1) / i + 1;

            if (tmp == a)
                break;

            a = tmp;
            x = a * i;
        }

        printf("Case #%d: %I64d\n", cas++, a * k);
    }
    return 0;
}