[Codeforces-911B] - Two Cakes

B. Two Cakes
time limit per test 1 second
memory limit per test 256 megabytes
input standard input
output standard output
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.

Ivan knows that there will be n people at the celebration (including himself), so Ivan has set nplates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:

Each piece of each cake is put on some plate;
Each plate contains at least one piece of cake;
No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.

Help Ivan to calculate this number x!

Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.

Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.

Examples
input
5 2 3
output
1
input
4 7 10
output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1cake on it.

In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3.

#include<bits/stdc++.h>
using namespace std;
int main(){
    int n, a, b,ans;
    while(cin>>n>>a>>b)
    {
        ans  = ;
        for(int i=;i<n;i++)
            ans = max(min(a/i,b/(n-i)),ans);
        cout<<ans<<endl;
    }
    return ;
}