UVA - 297Quadtrees(四分图)
| Time Limit: 3000MS | Memory Limit: Unknown | 64bit IO Format: %lld & %llu |
Description
A quadtree is a representation format used to encode images. The fundamental idea behind the quadtree is that any image can be split into four quadrants. Each quadrant may again be split in four sub quadrants, etc. In the quadtree, the image is represented by a parent node, while the four quadrants are represented by four child nodes, in a predetermined order.
Of course, if the whole image is a single color, it can be represented by a quadtree consisting of a single node. In general, a quadrant needs only to be subdivided if it consists of pixels of different colors. As a result, the quadtree need not be of uniform depth.
A modern computer artist works with black-and-white images of units, for a total of 1024 pixels per image. One of the operations he performs is adding two images together, to form a new image. In the resulting image a pixel is black if it was black in at least one of the component images, otherwise it is white.
This particular artist believes in what he calls the preferred fullness: for an image to be interesting (i.e. to sell for big bucks) the most important property is the number of filled (black) pixels in the image. So, before adding two images together, he would like to know how many pixels will be black in the resulting image. Your job is to write a program that, given the quadtree representation of two images, calculates the number of pixels that are black in the image, which is the result of adding the two images together.
In the figure, the first example is shown (from top to bottom) as image, quadtree, pre-order string (defined below) and number of pixels. The quadrant numbering is shown at the top of the figure.

Input Specification
The first line of input specifies the number of test cases (N) your program has to process.
The input for each test case is two strings, each string on its own line. The string is the pre-order representation of a quadtree, in which the letter 'p' indicates a parent node, the letter 'f' (full) a black quadrant and the letter 'e' (empty) a white quadrant. It is guaranteed that each string represents a valid quadtree, while the depth of the tree is not more than 5 (because each pixel has only one color).
Output Specification
For each test case, print on one line the text 'There are X black pixels.', where X is the number of black pixels in the resulting image.
Example Input
3
ppeeefpffeefe
pefepeefe
peeef
peefe
peeef
peepefefe
Example Output
There are 640 black pixels.
There are 512 black pixels.
There are 384 black pixels.
题解:
给你两个像素,让求两个像素合并起来的黑色像素的大小;
由于给的是四分图的先序遍历,那么这个图也就可以画出来了,于是可以边建图,边画图,如果遇到黑色像素f就画图,如果遇到p就递归建图;
其中x,y表示坐上点的位置,len代表当前图的面积;
代码:
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<queue>
using namespace std;
#define SI(x) scanf("%d",&x)
#define mem(x,y) memset(x,y,sizeof(x))
#define PI(x) printf("%d",x)
#define P_ printf(" ")
const int INF=0x3f3f3f3f;
typedef long long LL;
const int MAXN=40;
int buf[MAXN][MAXN];
char s[2020];
int cnt;
void draw(int &k,int x,int y,int len){
char ch=s[k++];
if(ch=='p'){
draw(k,x,y,len/2);
draw(k,x,y+len/2,len/2);
draw(k,x+len/2,y,len/2);
draw(k,x+len/2,y+len/2,len/2);
}
else if(ch=='f'){
for(int i=x;i<x+len;i++)
for(int j=y;j<y+len;j++)
if(!buf[i][j])buf[i][j]=1,cnt++;
}
}
int main(){
int T;
SI(T);
while(T--){
cnt=0;
mem(buf,0);
for(int i=0;i<2;i++){
mem(s,0);
scanf("%s",s);
int k=0;
draw(k,0,0,32);
}
printf("There are %d black pixels.\n",cnt);
}
return 0;
}
UVA - 297Quadtrees(四分图)的更多相关文章
- UVaLive 7375 Hilbert Sort (递归,四分图,模拟)
题意:告诉你一条希尔伯特曲线的大小,然后给你n 个人,及n 个人的坐标,你的起点是左下角,终点是右下角,按照希尔伯特的曲线去走,按照这个顺序给n个人排序, 按顺序输出每个人的名字! 析:这就是一个四分 ...
- 7.26T1四分图匹配
四分图匹配 题目描述 一天晚上,zzh 在做梦,忽然梦见了她. 见到她,zzh 也不去看她,只顾低头自语…… “噫,OI 这个东西,真是无奇不有.” “嘿,你又学了什么?” “嗯,学到了一种算法,”z ...
- UVA 11552 四 Fewest Flops
Fewest Flops Time Limit:2000MS Memory Limit:0KB 64bit IO Format:%lld & %llu Submit Statu ...
- Python可视化库Matplotlib的使用
一.导入数据 import pandas as pd unrate = pd.read_csv('unrate.csv') unrate['DATE'] = pd.to_datetime(unrate ...
- bzoj usaco 金组水题题解(2)
续.....TAT这回不到50题编辑器就崩了.. 这里塞40道吧= = bzoj 1585: [Usaco2009 Mar]Earthquake Damage 2 地震伤害 比较经典的最小割?..然而 ...
- Python的Matplotlib库简述
Matplotlib 库是 python 的数据可视化库import matplotlib.pyplot as plt 1.字符串转化为日期 unrate = pd.read_csv("un ...
- bzoj 4823 [Cqoi2017]老C的方块——网络流
题目:https://www.lydsy.com/JudgeOnline/problem.php?id=4823 一个不合法方案其实就是蓝线的两边格子一定选.剩下两部分四相邻格子里各选一个. 所以这个 ...
- unity3d之游戏优化
=============================================================================== 美术规格: 1.单个蒙皮网格渲染器2.一 ...
- python数据处理与机器学习
提纲 numpy: #genformtxt import numpy as np #genformtxtdata=np.genfromtxt("genfromtxtdata") # ...
随机推荐
- html5的自定义data-*属性与jquery的data()方法的使用
人们总喜欢往HTML标签上添加自定义属性来存储和操作数据.但这样做的问题是,你不知道将来会不会有其它脚本把你的自定义属性给重置掉,此外,你这样做也会导致html语法上不符合Html规范,以及一些其它副 ...
- mini-httpd源码分析-mini-httpd.c之外总结
version.h #define SERVER_SOFTWARE "mini_httpd/1.21 18oct2014" #define SERVER_URL "htt ...
- verilog 随笔
不是说你在代码里定义一个reg型变量,综合器就会综合处一个寄存器来,case必须在always块里,always里面的被赋值变量必须是reg型,这是语法的规定,只能遵守.写代码的时候不要加入触发器(不 ...
- 3.java.lang.ClassNotFoundException
指定的类不存在 这里主要考虑一下类的名称和路径是否正确即可,通常都是程序试图通过字符串来加载某个类时可能引发 异常 比如: 调用Class.forName(); 或者调用ClassLoad的finaS ...
- cad实时平移快捷键
1.按住鼠标滚轮,光标变成小手工具,可拖动画布 2.键盘按 p,光标变成小手工具
- 使用border-image实现类似iOS7的1px底边
使用border-image实现类似iOS7的1px底边 iOS7已经发布有一段时间,扁平化设计风格有很多值得称赞的地方,其中有很多设计细节都是值得研究的. 首先,来看下面iOS设置的截图中的bord ...
- as3 与js相互通信
1.as和js通讯实例 如果as3调用 JAVA script 中的函数直接在as中添加 if (ExternalInterface.available) { ExternalInterf ...
- Android View动画
Animation TypeEvaluator View的animate方法 ValueAnimator ObjectAnimator AnimatorSet 使用xml来创建动画 animation ...
- 用正则匹配一串字符串中的ip地址
IP地址有4段组成,每一段数字的范围为0-255,在一段文本中提取ip地址可以这样 $src = 'src = alsdlk ks sdf2.3.3.4 234.193.1.120.1232 d.23 ...
- SQL SERVER 2000/2005/2008数据库数据迁移到Oracle 10G细述
最近参与的一个系统涉及到把SQL Server 2k的数据迁移到Oracle 10G这一非功能需求.特将涉及到相关步骤列举如下供大家参考: 环境及现有资源: 1.OS: Windows 7 Enter ...