iOS 请求数据 error

解决办法如下:

0x1 ->请求数据时加上缺少的类型

AFHTTPSessionManager *manager = [selfAFHTTPSessionManager];
//    manager.responseSerializer.acceptableContentTypes = [NSSet setWithObject:@"text/html"];
    [manager GET:URLString parameters:parameters progress:nilsuccess:^(NSURLSessionDataTask * _Nonnull task, id  _Nullable responseObject) {
        if (success) {//并且code = 正确
            success(responseObject);
        }
        
    } failure:^(NSURLSessionDataTask * _Nullable task, NSError * _Nonnull error) {
        if (failure) {
            failure(error);
        }

    }];

0x2->服务器后台指定数据返回类型

<?php

    header("Content-Type:application/json;charset = utf-8");

    // 请求--get

    // 参数:userName passWord

    $userName = 

    $_GET["userName"];

    $passWord = 

    $_GET["passWord"];

    $respond = array("code"=>200,"userName"=>$userName,"title"=>"success");

    // 返回结果

    echo(json_encode($respond));

 

    // http://127.0.0.1/Login/Login2.php?userName=fa&passWord=123

?>