POJ1008Maya Calendar

http://poj.org/problem?id=1008&lang=default&change=true

这个题倒是不难，就是麻烦一点，但是还WA了几次都是因为处理天数的时候没处理好，因为Haab这个日历日期是从0开始的，所以当第一年的最后一天第364天，而如果输入的恰好是365天应该是第二年的，所以，那个天数要放在下面处理

 #include<cstdio>
 #include<cstring>
 #include<iostream>
 using namespace std ;
 int main()
 {
     int n ;
     scanf("%d",&n) ;
     printf("%d\n",n);
     for(int i =  ; i <= n ; i++)
     {
         int day,year ;
         char month[];
         scanf("%d",&day) ;
         getchar();
         cin>>month ;
         cin>>year ;
         int mon ;
         if(strcmp(month,"pop")==) mon =  ;
         if(strcmp(month,"no")==) mon =  ;
         if(strcmp(month,"zip")==) mon =  ;
         if(strcmp(month,"zotz")==) mon =  ;
         if(strcmp(month,"tzec")==) mon =  ;
         if(strcmp(month,"xul")==) mon =  ;
         if(strcmp(month,"yoxkin")==) mon =  ;
         if(strcmp(month,"mol")==) mon =  ;
         if(strcmp(month,"chen")==) mon =  ;
         if(strcmp(month,"yax")==) mon =  ;
         if(strcmp(month,"zac")==) mon =  ;
         if(strcmp(month,"ceh")==) mon =  ;
         if(strcmp(month,"mac")==) mon =  ;
         if(strcmp(month,"kankin")==) mon =  ;
         if(strcmp(month,"muan")==) mon =  ;
         if(strcmp(month,"pax")==) mon =  ;
         if(strcmp(month,"koyab")==) mon =  ;
         if(strcmp(month,"cumhu")==) mon =  ;
         if(strcmp(month,"uayet")==) mon =  ;
         int days = (year*)+(mon-)*+day;
         printf("%d ",days%%+);
         int Tdays = days%%+ ;
         if(Tdays == ) cout<<"imix";
         if(Tdays == ) cout<<"ik";
         if(Tdays == ) cout<<"akbal";
         if(Tdays == ) cout<<"kan";
         if(Tdays == ) cout<<"chicchan";
         if(Tdays == ) cout<<"cimi";
         if(Tdays == ) cout<<"manik";
         if(Tdays == ) cout<<"lamat";
         if(Tdays == ) cout<<"muluk";
         if(Tdays == ) cout<<"ok";
         if(Tdays == ) cout<<"chuen";
         if(Tdays == ) cout<<"eb";
         if(Tdays == ) cout<<"ben";
         if(Tdays == ) cout<<"ix";
         if(Tdays == ) cout<<"mem";
         if(Tdays == ) cout<<"cib";
         if(Tdays == ) cout<<"caban";
         if(Tdays == ) cout<<"eznab";
         if(Tdays == ) cout<<"canac";
         if(Tdays == ) cout<<"ahau";
         //int Tyears = (year*365)/260 ;
         int Tyears = days/;
         cout<<" "<<Tyears<<endl ;
     }
     return  ;
 }