Java [Leetcode 228]Summary Ranges

题目描述：

Given a sorted integer array without duplicates, return the summary of its ranges.

For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"].

解题思路：

相邻的两个数字若差距为1，则继续向后读，直到不满足条件为止，则把起始到终点的结果表示出来。如此，直到读到数组的最后位置为止。

代码如下：

public class Solution {
    public List<String> summaryRanges(int[] nums) {
    	List<String> result = new ArrayList<String>();
    	int length = nums.length;
    	for(int i = 0; i < nums.length; i++){
    		int front = nums[i];
    		while(i + 1 < nums.length && nums[i + 1] - nums[i] == 1)
    			i++;
    		int end = nums[i];
    		if(front == end)
    			result.add(front + "");
    		else
    			result.add(front + "->" + end);
    	}
    	return result;
    }
}