Glass Beadshttp://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1006


Time Limit: 2 Seconds      Memory Limit: 65536 KB

Once upon a time there was a famous actress. As you may expect, she played mostly Antique Comedies most of all. All the people loved her. But she was not interested in the crowds. Her big hobby were beads of any kind. Many bead makers were working for her and they manufactured new necklaces and bracelets every day. One day she called her main Inspector of Bead Makers (IBM) and told him she wanted a very long and special necklace.

The necklace should be made of glass beads of different sizes connected to each other but without any thread running through the beads, so that means the beads can be disconnected at any point. The actress chose the succession of beads she wants to have and the IBM promised to make the necklace. But then he realized a problem. The joint between two neighbouring beads is not very robust so it is possible that the necklace will get torn by its own weight. The situation becomes even worse when the necklace is disjoined. Moreover, the point of disconnection is very important. If there are small beads at the beginning, the possibility of tearing is much higher than if there were large beads. IBM wants to test the robustness of a necklace so he needs a program that will be able to determine the worst possible point of disjoining the beads.

The description of the necklace is a string A = a1a2 ... am specifying sizes of the particular beads, where the last character am is considered to precede character a1 in circular fashion.

The disjoint point i is said to be worse than the disjoint point j if and only if the string aiai+1 ... ana1 ... ai-1 is lexicografically smaller than the string ajaj+1 ... ana1 ... aj-1. String a1a2 ... an is lexicografically smaller than the string b1b2 ... bn if and only if there exists an integer i, i <= n, so that aj=bj, for each j, 1 <= j < i and ai < bi.

Input

The input consists of N cases. The first line of the
input contains only positive integer N. Then follow the cases. Each case
consists of exactly one line containing necklace description. Maximal length of
each description is 10000 characters. Each bead is represented by a lower-case
character of the english alphabet (a--z), where a < b ... z.

Output

For each case, print exactly one line containing
only one integer -- number of the bead which is the first at the worst possible
disjoining, i.e. such i, that the string A[i] is lexicographically smallest
among all the n possible disjoinings of a necklace. If there are more than one
solution, print the one with the lowest i.

Sample
Input

4
helloworld
amandamanda
dontcallmebfu
aaabaaa

Sample Output

10
11
6
5

题意:输出字典序最小的同构字符串首位置

最小表示法

#include<cstdio>
#include<cstring>
#include<algorithm>
#define N 10001
using namespace std;
char s[N];
int len;
int main()
{
int n,i,j,k;
scanf("%d",&n);
while(n--)
{
scanf("%s",s);
len=strlen(s);
i=; j=;
while(i<len&&j<len)
{
k=;
while(k<len && s[(i+k)%len]==s[(j+k)%len]) k++;
if(k==len) break;
if(s[(i+k)%len]<s[(j+k)%len]) j=max(j+k+,i+);
else i=max(i+k+,j+);
}
printf("%d\n",min(i,j)+);
}
}

zoj 2006 Glass Beads的更多相关文章

  1. POJ1509 Glass Beads

    Glass Beads Time Limit: 3000MS   Memory Limit: 10000K Total Submissions: 4314   Accepted: 2448 Descr ...

  2. POJ1509 Glass Beads(最小表示法 后缀自动机)

    Time Limit: 3000MS   Memory Limit: 10000K Total Submissions: 4901   Accepted: 2765 Description Once ...

  3. 【POJ1509】Glass Beads

    [POJ1509]Glass Beads [题目描述]给定字符串S,并规定首尾相连成环,求出最小字典序. [输入]输入有多个数据,第一行只包括正整数N,表示有N组数据.每个数据包括一行,输入该字符串. ...

  4. cogs 2123. [HZOI 2015] Glass Beads

    2123. [HZOI 2015] Glass Beads ★★★   输入文件:MinRepresentations.in   输出文件:MinRepresentations.out   简单对比时 ...

  5. UVALive 5545 Glass Beads

    Glass Beads Time Limit: 3000ms Memory Limit: 131072KB This problem will be judged on UVALive. Origin ...

  6. POJ 1509 Glass Beads

    Description 求字符串的最小循环表示. Sol SAM. 把原串复制一遍,建出SAM,然后每次选最小的一个跑 \(len\) 次,这就是最小循环表示的最后一个节点,然后 \(x-len+1\ ...

  7. 1509 -- Glass Beads POJ

    题意:求一个字符串的最小表示的开始下标 就当模板题写了 把字符串重复一遍,再建后缀自动机,贪心的选最小字典序在上面走len步 因为走出来的一定是子串,长度又是len,所以一定是原来的字符串旋转得到的, ...

  8. 杂项(最小表示法):HZOI 2015 Glass Beads

    [题目描述] 给定长度为n(n<=300000)的循环同构的字符串,定义最小表示为该字符串的字典序最小的同构表示,请输出这个表示. [输入格式] 第一行是串的长度,第二行是字符串. [输出格式] ...

  9. UVA 719 / POJ 1509 Glass Beads (最小表示法/后缀自动机)

    题目大意: 给出一个长度为N的字符串,求其字典序最小的循环同构. N<=10W. 算法讨论: 算法一.最小表示法.定义题. 算法二.后缀自动机. Codes: #include <iost ...

随机推荐

  1. Servlet过滤器介绍之原理分析

    zhangjunhd 的BLOG     写留言去学院学习发消息 加友情链接进家园 加好友 博客统计信息 51CTO博客之星 用户名:zhangjunhd 文章数:110 评论数:858 访问量:19 ...

  2. Redis 错误摘记篇

    yum安装的redis提示如下报错,大概意思就是配置文件和redis-server进程文件版本不一致.. [root@vm-10-104-28-24 yum.repos.d]# redis-serve ...

  3. Memory及其controller芯片整体测试方案(上篇)

    如果你最近想买手机,没准儿你一看价格会被吓到手机什么时候偷偷涨价啦! 其实对于手机涨价,手机制造商也是有苦难言,其中一个显著的原因是存储器芯片价格的上涨↗↗↗ >>> 存储器memo ...

  4. UVALive - 6886 Golf Bot 多项式乘法(FFT)

    题目链接: http://acm.hust.edu.cn/vjudge/problem/129724 Golf Bot Time Limit: 15000MS 题意 给你n个数,m个查询,对于每个查询 ...

  5. lintcode-34-N皇后问题 II

    34-N皇后问题 II 根据n皇后问题,现在返回n皇后不同的解决方案的数量而不是具体的放置布局. 样例 比如n=4,存在2种解决方案 标签 递归 思路 参考http://www.cnblogs.com ...

  6. C语言的世界

    大家好,我是一名大一的学生,我叫陈由钧,我来自计算机系,一开始选择这门专业的时候,是出于对计算机的热爱,我喜欢计算机,喜欢没事琢磨琢磨计算的各种程序,各种软件,所以我选择学习计算机这门专业,第一周我就 ...

  7. Perfmon - 脚本自动监控

    PerfMon-Windows性能监视器是个好东西,可以辅助我们分析发生问题时间段服务器资源占用情况,但是部署性能计数器确实一个相当麻烦的事情,往往这种枯燥的事别人还做不了,只能由我们这些希望获取到P ...

  8. vue中使用monaco-editor打包文件混乱的问题

    之前讲述了怎么在vue项目中使用monaco-editor (https://www.cnblogs.com/XHappyness/p/9414177.html),使用是正常的,虽然 npm run ...

  9. 载入其他同名源文件导致vs编译错误

    今天下午工程编译的时候总是通不过,提示1,某个类没有某个成员,可是我去该类的头文件下查看,确实包括了这个成员啊.2,没有某个类,可是我明明定义了的. 检查了好久才发现 原来是,我打开了其他工程下的某一 ...

  10. MySQL中使用trim()删除两侧字符

    在某些情况下由于程序没处理好,导致数据表中有些字段的值会有空白字符出现,如 这样如果在严格比对name时会匹配不到.trim()函数可以解决这样的问题 作为trim()函数的子集,ltrim()函数是 ...