leetcode-mid-array-3 Longest Substring Without Repeating Characters
mycode 99.21%
class Solution(object):
def lengthOfLongestSubstring(self, s):
"""
:type s: str
:rtype: int
"""
maxlen = 0
temp =''
for i in s:
if i not in temp:
temp += i
else:
maxlen = max(maxlen,len(temp))
temp = temp[temp.index(i)+1:] + i
maxlen = max(maxlen,len(temp))
return maxlen
注意:下面这种方式也可以及时更替最大长度
def lengthOfLongestSubstring(s):
l = 0
ls = ""
for i in s:
if i in ls:
ls = ls[ls.index(i)+1:]
ls += i
if len(ls) > l:
#maxres = max(maxres,len(ls))
l = len(ls)
return l
lengthOfLongestSubstring("abcdvdf")
leetcode-mid-array-3 Longest Substring Without Repeating Characters的更多相关文章
- LeetCode 第 3 题(Longest Substring Without Repeating Characters)
LeetCode 第 3 题(Longest Substring Without Repeating Characters) Given a string, find the length of th ...
- Leetcode经典试题:Longest Substring Without Repeating Characters解析
题目如下: Given a string, find the length of the longest substring without repeating characters. Example ...
- 【LeetCode】3 、Longest Substring Without Repeating Characters
题目等级:Medium 题目描述: Given a string, find the length of the longest substring without repeating chara ...
- leetcode第三题Longest Substring Without Repeating Characters java
Longest Substring Without Repeating Characters Given a string, find the length of the longest substr ...
- leetcode第三题--Longest Substring Without Repeating Characters
Problem:Given a string, find the length of the longest substring without repeating characters. For e ...
- LeetCode(3)Longest Substring Without Repeating Characters
题目: Given a string, find the length of the longest substring without repeating characters. For examp ...
- LeetCode解题笔记 - 3. Longest Substring Without Repeating Characters
Given a string, find the length of the longest substring without repeating characters. Examples: Giv ...
- LeetCode第三题—— Longest Substring Without Repeating Characters(最长无重复子字符串)
题目描述 Given a string, find the length of the longest substring without repeating characters. Example ...
- LeetCode Hash Table 3. Longest Substring Without Repeating Characters
HashMap的应用可以提高查找的速度,键key,值value的使用拜托了传统数组的遍历查找方式,对于判断一个字符或者字符串是否已经存在的问题可以非常好的解决.而本题需要解决的问题就是判断新遍历到的字 ...
- 【LeetCode算法题库】Day1:TwoSums & Add Two Numbers & Longest Substring Without Repeating Characters
[Q1] Given an array of integers, return indices of the two numbers such that they add up to a specif ...
随机推荐
- JS基础篇--JS获取元素的宽高以及offsetTop,offsetLeft等的属性值
$(obj).width()与$(obj).height() $(obj).width()与$(obj).height() :jquery方式获取元素的宽高,不包括滚动条与工具条 $(obj).wid ...
- 题解 CF1119A 【Ilya and a Colorful Walk】
此题就是:给你一个数组,让你找出两个不同的元素,并让它们的下标差距最大. 思路:从2到n,如果与1不同,记录距离,与原数比较,取大. 从1到n-1,如果与n不同,记录距离,与原数比较,取大. AC代码 ...
- 画一个心送给心爱的小姐姐,Python绘图库Turtle
Python绘图库Turtle Turtle介绍 Turtle是Python内嵌的绘制线.圆以及其他形状(包括文本)的图形模块. 一个Turtle实际上是一个对象,在导入Turtle模块时,就创建了对 ...
- 搜索专题: HDU1242 Rescue
Rescue Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Sub ...
- unsolved question's solution
因为很懒,没有时间,只会口胡等等原因,所以有些题目就不打code了 $luogu:$ P1973 [NOI2011]Noi嘉年华: 时间离散化,预处理一个区间$[l,r]$内的最多活动个数$in[l] ...
- 多线程测试工具groboutils的使用
一直使用junit做为服务测试框架,感觉不错.最近有人反映在高并发的情况下,存在服务调不到.无奈再次打开单元测试模拟高并发的 情况,却发现junit不支持并发测试 引入groboutils ...
- 【COSMOS】跨链协议IBC概述
一.什么是IBC? IBC是链间通信协议的缩写(Inter-Blockchain Communication Protocol).通过数据包交换在多个不同的区块链网络之间转移数据和状态信息.最初的用途 ...
- express与koa对比
使用体验koaconst Koa = require('koa');const app = new Koa();app.use(ctx => { ctx.body = 'Hello Koa'; ...
- <input type="radio">单选按钮
转自:http://www.divcss5.com/html/h490.shtml1 <form> 男性: <input type="radio" checked ...
- mail - 发送和接收邮件
SYNOPSIS(总览) mail [-iInv ] [-s subject ] [-c cc-addr ] [-b bcc-addr ] to-addr... mail [-iInNv -f ] [ ...