leetcode-mid-array-3 Longest Substring Without Repeating Characters
mycode 99.21%
class Solution(object):
def lengthOfLongestSubstring(self, s):
"""
:type s: str
:rtype: int
"""
maxlen = 0
temp =''
for i in s:
if i not in temp:
temp += i
else:
maxlen = max(maxlen,len(temp))
temp = temp[temp.index(i)+1:] + i
maxlen = max(maxlen,len(temp))
return maxlen
注意:下面这种方式也可以及时更替最大长度
def lengthOfLongestSubstring(s):
l = 0
ls = ""
for i in s:
if i in ls:
ls = ls[ls.index(i)+1:]
ls += i
if len(ls) > l:
#maxres = max(maxres,len(ls))
l = len(ls)
return l
lengthOfLongestSubstring("abcdvdf")
leetcode-mid-array-3 Longest Substring Without Repeating Characters的更多相关文章
- LeetCode 第 3 题(Longest Substring Without Repeating Characters)
LeetCode 第 3 题(Longest Substring Without Repeating Characters) Given a string, find the length of th ...
- Leetcode经典试题:Longest Substring Without Repeating Characters解析
题目如下: Given a string, find the length of the longest substring without repeating characters. Example ...
- 【LeetCode】3 、Longest Substring Without Repeating Characters
题目等级:Medium 题目描述: Given a string, find the length of the longest substring without repeating chara ...
- leetcode第三题Longest Substring Without Repeating Characters java
Longest Substring Without Repeating Characters Given a string, find the length of the longest substr ...
- leetcode第三题--Longest Substring Without Repeating Characters
Problem:Given a string, find the length of the longest substring without repeating characters. For e ...
- LeetCode(3)Longest Substring Without Repeating Characters
题目: Given a string, find the length of the longest substring without repeating characters. For examp ...
- LeetCode解题笔记 - 3. Longest Substring Without Repeating Characters
Given a string, find the length of the longest substring without repeating characters. Examples: Giv ...
- LeetCode第三题—— Longest Substring Without Repeating Characters(最长无重复子字符串)
题目描述 Given a string, find the length of the longest substring without repeating characters. Example ...
- LeetCode Hash Table 3. Longest Substring Without Repeating Characters
HashMap的应用可以提高查找的速度,键key,值value的使用拜托了传统数组的遍历查找方式,对于判断一个字符或者字符串是否已经存在的问题可以非常好的解决.而本题需要解决的问题就是判断新遍历到的字 ...
- 【LeetCode算法题库】Day1:TwoSums & Add Two Numbers & Longest Substring Without Repeating Characters
[Q1] Given an array of integers, return indices of the two numbers such that they add up to a specif ...
随机推荐
- java基础笔记(3)
捕获异常: try{ ...... }catch(Exception e){ ...... }finally{ ...... } 注意:在写多重catch时需先小后大: 自定义异常: String字符 ...
- [BZOJ 4025]二分图(线段树分治+带边权并查集)
[BZOJ 4025]二分图(线段树分治+带边权并查集) 题面 给出一个n个点m条边的图,每条边会在时间s到t出现,问每个时间的图是否为一个二分图 \(n,m,\max(t_i) \leq 10^5\ ...
- [FJOI2007]轮状病毒 题解(dp(找规律)+高精度)
[FJOI2007]轮状病毒 题解(dp(找规律)+高精度) 标签:题解 阅读体验:https://zybuluo.com/Junlier/note/1335733 没什么好说的,直接把规律找出来,有 ...
- Scrapy 教程(九)-日志系统
最新版本的 scrapy 已经废弃了 scrapy.log 的使用,赞成显示调用python标准日志记录. Python 内建日志系统 import logging ### python 内建 log ...
- HNUSTOJ-1521 塔防游戏
1521: 塔防游戏 时间限制: 1 Sec 内存限制: 128 MB提交: 117 解决: 38[提交][状态][讨论版] 题目描述 小明最近迷上了塔防游戏,塔防游戏的规则就是在地图上建炮塔,用 ...
- ps的一点快捷键
选区工具快捷键(shift alt很重要) 按M键切换到选区工具 矩形选区-> shift 正方形 shift+m 矩形/椭圆来回切换 参考线:alt+v 选中上方的工具 alt+v+e 新建参 ...
- JDK集合框架源码分析 - 简单概要
1.类继承体系 在集合框架的类继承体系中,最顶层有两个接口Collection.Map: Collection 表示一组纯数据 Map 表示一组key-value对 Collection的类继承体系: ...
- 修改默认select样式
<style type="text/css"> .select_demo,.select_list { width: 400px; height: 60px; } .s ...
- Linux服务器调优
Linux内核参数 http://space.itpub.net/17283404/viewspace-694350 net.ipv4.tcp_syncookies = 表示开启SYN Cookies ...
- React 应用设计之道 - curry 化妙用
使用 React 开发应用,给予了前端工程师无限"组合拼装"快感.但在此基础上,组件如何划分,数据如何流转等应用设计都决定了代码层面的美感和强健性. 同时,在 React 世界里提 ...