zip拉链操作

def zip[U](other: org.apache.spark.rdd.RDD[U])(implicit evidence$10: scala.reflect.ClassTag[U]): org.apache.spark.rdd.RDD[(String, U)]

scala> val rdd1=sc.makeRDD(Array("apple","pear","grape","egg","elephant"))

rdd1: org.apache.spark.rdd.RDD[String] = ParallelCollectionRDD[23] at makeRDD at <console>:24

scala> val rdd2=sc.makeRDD(List(20,5,8,6,3))

rdd2: org.apache.spark.rdd.RDD[Int] = ParallelCollectionRDD[24] at makeRDD at <console>:24

scala> rdd1.zip(rdd2).collect
res35: Array[(String, Int)] = Array((apple,20), (pear,5), (grape,8), (egg,6), (elephant,3))

scala> val rdd3=rdd1 zip rdd2

rdd3: org.apache.spark.rdd.RDD[(String, Int)] = ZippedPartitionsRDD2[27] at zip at <console>:28

scala> rdd3.collect

res36: Array[(String, Int)] = Array((apple,20), (pear,5), (grape,8), (egg,6), (elephant,3))

-------------------------

def combineByKey[C](createCombiner: Int => C,mergeValue: (C, Int) => C,mergeCombiners: (C, C) => C): org.apache.spark.rdd.RDD[(String, C)]
def combineByKey[C](createCombiner: Int => C,mergeValue: (C, Int) => C,mergeCombiners: (C, C) => C,numPartitions: Int): org.apache.spark.rdd.RDD[(String, C)]
def combineByKey[C](createCombiner: Int => C,mergeValue: (C, Int) => C,mergeCombiners: (C, C) => C,partitioner: org.apache.spark.Partitioner,mapSideCombine: Boolean,serializer: org.apache.spark.serializer.Serializer): org.apache.spark.rdd.RDD[(String, C)]

def combineByKey[C](

createCombiner: V => C,

mergeValue: (C, V) => C,

mergeCombiners: (C, C) => C,       n

umPartitions: Int): RDD[(K, C)] = self.withScope {

combineByKeyWithClassTag(createCombiner, mergeValue, mergeCombiners, numPartitions)(null)

}

scala> rdd3.collect
res53: Array[(String, Int)] = Array((apple,2), (pear,1), (grape,2), (egg,1), (elephant,1))

scala> val rdd4=rdd3.combineByKey(List(_),(x:List[Int],v:Int)=>x:+v,(m:List[Int],n:List[Int])=>m++n)
rdd4: org.apache.spark.rdd.RDD[(String, List[Int])] = ShuffledRDD[35] at combineByKey at <console>:30

scala> rdd4.collect

res51: Array[(String, List[Int])] = Array((egg,List(1)), (elephant,List(1)), (pear,List(1)), (apple,List(2)), (grape,List(2)))

scala> val rdd4=rdd3.map(x=>(x._2,x._1))

rdd4: org.apache.spark.rdd.RDD[(Int, String)] = MapPartitionsRDD[33] at map at <console>:30

scala> val rdd5=rdd4.combineByKey(List(_),(x:List[String],v:String)=>x:+v,(m:List[String],n:List[String])=>m++n)
rdd5: org.apache.spark.rdd.RDD[(Int, List[String])] = ShuffledRDD[37] at combineByKey at <console>:32

scala> rdd5.collect

res52: Array[(Int, List[String])] = Array((1,List(pear, egg, elephant)), (2,List(apple, grape)))

--------------------

scala> val rdd1=sc.makeRDD(Array("apple","apple","pear","egg","hellokitty","egg","apple"))

rdd1: org.apache.spark.rdd.RDD[String] = ParallelCollectionRDD[4] at makeRDD at <console>:24

scala> rdd1.countByValue

res1: scala.collection.Map[String,Long] = Map(hellokitty -> 1, egg -> 2, pear -> 1, apple -> 3)

scala> val map1=rdd1.countByValue
map1: scala.collection.Map[String,Long] = Map(hellokitty -> 1, egg -> 2, pear -> 1, apple -> 3)

scala> val rdd2=sc.makeRDD(map1.toList)

rdd2: org.apache.spark.rdd.RDD[(String, Long)] = ParallelCollectionRDD[21] at makeRDD at <console>:28

scala> rdd2.collect

res5: Array[(String, Long)] = Array((hellokitty,1), (egg,2), (pear,1), (apple,3))

-------------------

scala> val rdd1=sc.makeRDD(Array("apple","apple","pear","egg","hellokitty","egg","apple"))

rdd1: org.apache.spark.rdd.RDD[String] = ParallelCollectionRDD[28] at makeRDD at <console>:24

scala> val rdd2=rdd1.map(x=>(x,1))

rdd2: org.apache.spark.rdd.RDD[(String, Int)] = MapPartitionsRDD[29] at map at <console>:26

scala> rdd2.collect

res33: Array[(String, Int)] = Array((apple,1), (apple,1), (pear,1), (egg,1), (hellokitty,1), (egg,1), (apple,1))

scala> rdd2.partitions.size
res34: Int = 4

scala> rdd2.reduceByKey(_+_).collect
res36: Array[(String, Int)] = Array((hellokitty,1), (egg,2), (pear,1), (apple,3))

scala> rdd2.reduceByKey(_+_,2).partitions.size //shuffile重新分为2个分区
res37: Int = 2

-------------------------------

shuffle操作可以重新分区,指定分区数

进行 shuffle 操作的是是很消耗系统资源的,需要写入到磁盘并通过网络传输,有时还需要对数据进行排序.常见的 Transformation 操作如:repartition,join,cogroup,以及任何 *By 或者 *ByKey 的 Transformation 都需要 shuffle

--------------------------------------

scala> val rdd2=rdd1.map(x=>(x,1))
rdd2: org.apache.spark.rdd.RDD[(String, Int)] = MapPartitionsRDD[29] at map at <console>:26

scala> rdd2.collect
res39: Array[(String, Int)] = Array((apple,1), (apple,1), (pear,1), (egg,1), (hellokitty,1), (egg,1), (apple,1))

scala> rdd2.combineByKey(x=>x,(c:Int,n:Int)=>c+n,(c1:Int,c2:Int)=>c1+c2).collect
res41: Array[(String, Int)] = Array((hellokitty,1), (egg,2), (pear,1), (apple,3))

scala> rdd1.countByValue()
res42: scala.collection.Map[String,Long] = Map(hellokitty -> 1, egg -> 2, pear -> 1, apple -> 3)

scala> rdd2.reduceByKey(_+_).collect
res44: Array[(String, Int)] = Array((hellokitty,1), (egg,2), (pear,1), (apple,3))

-------------------------------

scala> val rdd3=rdd1.map(x=>(1,x))

rdd3: org.apache.spark.rdd.RDD[(Int, String)] = MapPartitionsRDD[40] at map at <console>:26

scala> rdd3.collect

res45: Array[(Int, String)] = Array((1,apple), (1,apple), (1,pear), (1,egg), (1,hellokitty), (1,egg), (1,apple))

scala> rdd3.combineByKey(x=>List(x),(c:List[String],y:String)=>c:+y,(c1:List[String],c2:List[String])=>c1++c2).collect
res49: Array[(Int, List[String])] = Array((1,List(apple, apple, pear, egg, hellokitty, egg, apple)))

---------------------------------------------

scala> val rdd00=sc.makeRDD(List(("a",1),("b",1),("a",3),("ba",3),("b",1),("g",10)),2)

rdd00: org.apache.spark.rdd.RDD[(String, Int)] = ParallelCollectionRDD[44] at makeRDD at <console>:24

scala> val rdd3=rdd00.map(x=>(x._2,x._1))

rdd3: org.apache.spark.rdd.RDD[(Int, String)] = MapPartitionsRDD[45] at map at <console>:26

scala> rdd3.collect

res51: Array[(Int, String)] = Array((1,a), (1,b), (3,a), (3,ba), (1,b), (10,g))

scala> rdd3.groupByKey().collect

res53: Array[(Int, Iterable[String])] = Array((10,CompactBuffer(g)), (1,CompactBuffer(a, b, b)), (3,CompactBuffer(a, ba)))

scala> rdd3.combineByKey(x=>List(x),(c:List[String],y:String)=>c:+y,(c1:List[String],c2:List[String])=>c1++c2).collect

res54: Array[(Int, List[String])] = Array((10,List(g)), (1,List(a, b, b)), (3,List(a, ba)))

-----------------------

distinct(numPartitions:Int) 去重的同时重新分区

scala> val bb=sc.makeRDD(Array(1,1,2,1,8,6,8,4,5,4),2)

bb: org.apache.spark.rdd.RDD[Int] = ParallelCollectionRDD[81] at makeRDD at <console>:25

scala> bb.distinct(1).partitions.size

res61: Int = 1

scala> bb.distinct(3).partitions.size

res62: Int = 3

----------------------

def randomSplit(weights: Array[Double],seed: Long): Array[org.apache.spark.rdd.RDD[Int]]

randomSplit操作根据weights权重将一个RDD分割为多个RDD。权重越高,划分到的几率越大,权重的总和加起来为1,否则会不正常

scala> val split=aa.randomSplit(Array(0.1,0.2,0.3,0.4))

split: Array[org.apache.spark.rdd.RDD[Int]] = Array(MapPartitionsRDD[165] at randomSplit at <console>:27, MapPartitionsRDD[166] at randomSplit at <console>:27, MapPartitionsRDD[167] at randomSplit at <console>:27, MapPartitionsRDD[168] at randomSplit at <console>:27)

scala> split(0).count

res94: Long = 11

scala> split(1).count

res95: Long = 19

scala> split(2).count

res96: Long = 34

scala> split(3).count

res97: Long = 36

-----------------------------------------------------

def glom(): org.apache.spark.rdd.RDD[Array[Int]]

glom将每个分区中的元素放到一个数组里,变成和分区数一样多的数据

scala> val bb=sc.makeRDD(1 to 10,3)

bb: org.apache.spark.rdd.RDD[Int] = ParallelCollectionRDD[203] at makeRDD at <console>:25

scala> bb.glom().collect

res127: Array[Array[Int]] = Array(Array(1, 2, 3), Array(4, 5, 6), Array(7, 8, 9, 10))

spark 常用技巧总结2的更多相关文章

  1. spark 常用技巧总结

    解析url scala> import java.net.URLimport java.net.URL scala> val urlstr="http://www.baidu.c ...

  2. 【shell 大系】Linux Shell常用技巧

    在最近的日常工作中由于经常会和Linux服务器打交道,如Oracle性能优化.我们数据采集服务器的资源利用率监控,以及Debug服务器代码并解决其效率和稳定性等问题.因此这段时间总结的有关Linux ...

  3. oracle存储过程常用技巧

    我们在进行pl/sql编程时打交道最多的就是存储过程了.存储过程的结构是非常的简单的,我们在这里除了学习存储过程的基本结构外,还会学习编写存储过程时相关的一些实用的知识.如:游标的处理,异常的处理,集 ...

  4. Vim 常用技巧:

    Vim 常用技巧: 将回车由默认的8个空格改为4个空格: 命令:set sw=4 修改tab为4空格: 命令:set ts=4 设置每一级的缩进长度: 命令:set shiftwidth=4 设置文件 ...

  5. JS~~~ 前端开发一些常用技巧 模块化结构 &&&&& 命名空间处理 奇技淫巧!!!!!!

    前端开发一些常用技巧               模块化结构       &&&&&     命名空间处理 奇技淫巧!!!!!!2016-09-29    17 ...

  6. Android ListView 常用技巧

    Android ListView 常用技巧 Android TextView 常用技巧 1.使用ViewHolder提高效率 ViewHolder模式充分利用了ListView的视图缓存机制,避免了每 ...

  7. JavaScript常用技巧总结(持续添加中...)

    在我学习过程中收集的一些常用技巧: typeof x !== undifined 判断x是否已定义: x === Object(x)  判断x是否为对象: Object.keys(x).length ...

  8. Eclipse调试常用技巧(转)

    Eclipse调试常用技巧 转自http://daimojingdeyu.iteye.com/blog/633824 1. 条件断点 断点大家都比较熟悉,在Eclipse Java 编辑区的行头双击就 ...

  9. AS技巧合集「常用技巧篇」

    转载:http://www.apkbus.com/forum.php?mod=viewthread&tid=254723&extra=page%3D2%26filter%3Dautho ...

随机推荐

  1. Word中选择中内容后变成C,VMware 虚拟中Ctrl键一直被按住了

    Word中选择中内容后变成C: 解决办法:关闭金山词霸的[划词翻译]功能即可. VMware 虚拟中Ctrl键一直被按住了: 解决办法:关闭金山词霸的[取词翻译]功能即可.

  2. Base64 转 图片

    static void Main(string[] args) { string s = "iVBORw0KGgoAAAANSUhEUgAAAFAAAABQCAIAAAABc2X6AAAAC ...

  3. 校验台湾身份证号码的js脚本

    网上搜了一下,居然没有,只好自己写一个. //台湾地区身份证校验 function IsTWIdcard(idcard){ if(/^[A-Z][1-2]\d{8}$/.test(idcard)) { ...

  4. java经典5种 FlowLayout 、BorderLayout、GridLayout、GridBagLayout、CardLayout布局

    Java 程序通过jvm可以很好的移植到其他平台上,但是java 生成的图形界面样式,在不使用布局的情况下,往往需要重新设定大小,才能在新的平台上调整到最佳样式.这是由于组件的最佳大小 往往是与平台相 ...

  5. Java判断两个List是否相同

    1.利用Java中为List提供的方法retainAll() /** * 判断两个List内的元素是否相同 * <p> * 此方法有bug 见Food.class * * @param l ...

  6. 关于Javascript闭包(Closure)

    闭包(closure)是Javascript语言的一个难点,也是它的特色,很多高级应用都要依靠闭包实现. 一.变量的作用域 要理解闭包,首先必须理解Javascript特殊的变量作用域. 变量的作用域 ...

  7. 将 GitHub 的某人的特定仓库复制到自己的账户下 的方法

    访问仓库页面,点击 Fork 按钮创建自己的仓库 Fork 就是将 GitHub 的某个特定仓库复制到自己的账户下. Fork 出的仓库与原仓库是两个不同的仓库,开发者可以随意编辑. 新建的仓库名为& ...

  8. python 指定文件编码的方法

    import sys reload(sys) sys.setdefaultencoding('utf-8')

  9. Bisecting KMeans (二分K均值)算法讲解及实现

    算法原理 由于传统的KMeans算法的聚类结果易受到初始聚类中心点选择的影响,因此在传统的KMeans算法的基础上进行算法改进,对初始中心点选取比较严格,各中心点的距离较远,这就避免了初始聚类中心会选 ...

  10. 刚刚研究了下ipv6,尝试配置内网VPS的IPv6地址

    刚刚研究了下ipv6,尝试配置内网VPS的IPv6地址是3台设备,分别是客户机Windows系统.核心交换机.PPPoE拨号的路由器 第一步:在PPPoE拨号的路由器上面查看ppp0拨号的地址 ifc ...