Educational Codeforces Round 65 (Rated for Div. 2) A. Telephone Number
链接:https://codeforces.com/contest/1167/problem/A
题意:
A telephone number is a sequence of exactly 11 digits, where the first digit is 8. For example, the sequence 80011223388 is a telephone number, but the sequences 70011223388and 80000011223388 are not.
You are given a string ss of length nn, consisting of digits.
In one operation you can delete any character from string ss. For example, it is possible to obtain strings 112, 111 or 121 from string 1121.
You need to determine whether there is such a sequence of operations (possibly empty), after which the string ss becomes a telephone number.
思路:
找到第一个8出现的位置。再把多余的减掉看是否符合。
代码:
#include <bits/stdc++.h>
using namespace std; typedef long long LL;
const int MAXN = 1e5+10; int main()
{
int t;
cin >> t;
while (t--)
{
int n;
string s;
cin >> n >> s;
int cnt = -1;
for (int i = 0;i < s.length();i++)
{
if (s[i] == '8')
{
cnt = i;
break;
}
}
if (cnt == -1)
cout << "NO" << endl;
else if (s.length() - cnt < 11)
cout << "NO" << endl;
else
cout << "YES" << endl;
} return 0;
}
Educational Codeforces Round 65 (Rated for Div. 2) A. Telephone Number的更多相关文章
- Educational Codeforces Round 65 (Rated for Div. 2)题解
Educational Codeforces Round 65 (Rated for Div. 2)题解 题目链接 A. Telephone Number 水题,代码如下: Code #include ...
- Educational Codeforces Round 65 (Rated for Div. 2) D. Bicolored RBS
链接:https://codeforces.com/contest/1167/problem/D 题意: A string is called bracket sequence if it does ...
- Educational Codeforces Round 65 (Rated for Div. 2) C. News Distribution
链接:https://codeforces.com/contest/1167/problem/C 题意: In some social network, there are nn users comm ...
- Educational Codeforces Round 65 (Rated for Div. 2) B. Lost Numbers
链接:https://codeforces.com/contest/1167/problem/B 题意: This is an interactive problem. Remember to flu ...
- Educational Codeforces Round 65 (Rated for Div. 2)B. Lost Numbers(交互)
This is an interactive problem. Remember to flush your output while communicating with the testing p ...
- [ Educational Codeforces Round 65 (Rated for Div. 2)][二分]
https://codeforc.es/contest/1167/problem/E E. Range Deleting time limit per test 2 seconds memory li ...
- Educational Codeforces Round 65 (Rated for Div. 2)
A:签到. #include<bits/stdc++.h> using namespace std; #define ll long long #define inf 1000000010 ...
- Educational Codeforces Round 65 (Rated for Div. 2) E. Range Deleting(思维+coding)
传送门 参考资料: [1]:https://blog.csdn.net/weixin_43262291/article/details/90271693 题意: 给你一个包含 n 个数的序列 a,并且 ...
- Educational Codeforces Round 65 (Rated for Div. 2)(ACD)B是交互题,不怎么会
A. Telephone Number A telephone number is a sequence of exactly 11 digits, where the first digit is ...
随机推荐
- Hadoop- 分布式资源管理YARN架构讲解
YARN是分布式资源管理,每一台机器都要去管理该台计算机的资源,Yarn负责为MapReduce程序分配运算硬件资源.每一台机器的管理者叫 NodeManager,整个集群的管理者管理着整个集群的No ...
- ES禁用_source不会影响聚合
From Elasticsearch's website: The _source field contains the original JSON document body that was pa ...
- L94
Early-morning births are genetically programmed THE notion that nothing good happens after midnight ...
- hdu-4417 Super Mario(树状数组 + 划分树)
题目链接: Super Mario Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Other ...
- 树莓派与 Python —— GPIO
首先来直观地认识树莓派提供的 40 个引脚(GPIO,general purpose i/o,接收外界输入,并向外界提供运算处理后的输出): 1. 安装 从远程库(repositories)中下载安装 ...
- CodeForces - 613D:Kingdom and its Cities(虚树+DP)
Meanwhile, the kingdom of K is getting ready for the marriage of the King's daughter. However, in or ...
- 【C++基础】形参实参
c++规定:一个函数的默认实参既可以在定义中,也可在声明中指定,但在一个文件(准确的说,是一个作用域)中只能为一个形参指定默认实参一次
- 【Lintcode】112.Remove Duplicates from Sorted List
题目: Given a sorted linked list, delete all duplicates such that each element appear only once. Examp ...
- vue之axios请求数据本地json
写给自己的话:静态的json文件要记得放在static文件夹下,想打自己 1.下载插件 npm install axios --save 2.在main.js下引用axios import axios ...
- 自动拆装箱(int,Integer)
包装类型Java语言是一个面向对象的语言,但是Java中的基本数据类型却是不面向对象的,这在实际使用时存在很多的不便,为了解决这个不足,在设计类时为每个基本数据类型设计了一个对应的类进行代表,这样八个 ...