PATA1082Read Number in Chinese

• 有几点需要注意的地方一是将right转化为与left在在同一节

while (left + 4 <= right)
{
	right -= 4;//每次将right移动4位，直到left与right在同一节
}

• 二是输出的时候每一节中的位，以及后面的亿和万

参考代码：

#define _CRT_SECURE_NO_WARNINGS
#include<cstdio>
#include<cstring>
#include<cstdlib>

char num[10][5] = { "ling","yi","er","san","si","wu","liu","qi","ba","jiu" };
char wei[5][5] = { "Shi","Bai","Qian","Wan","Yi" };

int main()
{
	char str[15];
	scanf("%s", str);//按字符串输入数字
	int len = strlen(str);
	int left = 0, right = len - 1;//分别指向字符串的首尾元素
	if (str[0] == '-')
	{
		printf("Fu");
		left++;
	}

	while (left + 4 <= right)
	{
		right -= 4;//每次将right移动4位，直到left与right在同一节
	}
	while (left < len)
	{
		bool flag = false;//flag==false表示没有累计的0

		while (left <= right)
		{
			if (left > 0 && str[left] == '0')
			{
				flag = true;
			}
			else
			{
				if (flag == true)
				{
					printf(" ling");
					flag = false;
				}
				if (left > 0) printf(" ");//只要不是首位都要在每个后面输出空格
				printf("%s", num[str[left] - '0']);//输出当前位数字

				if (left != right)
				{
					printf(" %s", wei[right - left - 1]);
				}
			}
			left++;
		}
		if (right != len - 1)
		{
			printf(" %s", wei[(len - 1 - right) / 4 + 2]);
		}
		right += 4;
	}

	system("pause");
	return 0;
}