Severe acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global threat in mid-March 2003. To minimize transmission to others, the best strategy is to separate the suspects from others. In the Not-Spreading-Your-Sickness University (NSYSU), there are many student groups. Students in the same group intercommunicate with each other frequently, and a student may join several groups. To prevent the possible transmissions of SARS, the NSYSU collects the member lists of all student groups, and makes the following rule in their standard operation procedure (SOP).
Once a member in a group is a suspect, all members in the group are suspects.
However, they find that it is not easy to identify all the suspects when a student is recognized as a suspect. Your job is to write a program which finds all the suspects.
Input
The input file contains several cases. Each test case begins with two integers n and m in a line, where n is the number of students, and m is the number of groups. You may assume that 0 < n ≤ 30000 and 0 ≤ m ≤ 500. Every student is numbered by a unique integer between 0 and n−1, and initially student 0 is recognized as a suspect in all the cases. This line is followed by m member lists of the groups, one line per group. Each line begins with an integer k by itself representing the number of members in the group. Following the number of members, there are k integers representing the students in this group. All the integers in a line are separated by at least one space. A case with n = 0 and m = 0 indicates the end of the input, and need not be processed.
Output
For each case, output the number of suspects in one line.
Sample Input
100 4 2 1 2 5 10 13 11 12 14 2 0 1 2 99 2 200 2 1 5 5 1 2 3 4 5 1 0 0 0
Sample Output
4 1 1

题目意思:

有n个人,m个学习,每个信息表示k个人曾经是一个团体(一个团体的人只要一人有病,团体所有人都可能患病)现在已经知道0号有病

问你有几个人可能会患病

分析:

简单的计数并查集

最后统计一些和0在一个集合里面的人数就是可能患病总人数

code:

#include <iostream>
#include<algorithm>
#include <cstdio>
#include<cstring>
#include<math.h>
#include<memory>
using namespace std;
typedef long long LL;
#define max_v 30000
int pa[max_v];
int rk[max_v];
int n,m;
void make_set(int x)
{
pa[x]=x;
rk[x]=;
}
int find_set(int x)
{
if(x!=pa[x])
pa[x]=find_set(pa[x]);
return pa[x];
}
void union_set(int x,int y)
{
x=find_set(x);
y=find_set(y);
if(x==y)
return ;
if(rk[x]>rk[y])
pa[y]=x;
else
{
pa[x]=y;
if(rk[x]==rk[y])
rk[y]++;
}
}
int main()
{
while(~scanf("%d %d",&n,&m))
{
if(n==&&m==)
break;
for(int i=;i<=n-;i++)
make_set(i);
for(int i=;i<=m;i++)
{
int k;
scanf("%d",&k);
int x,y;
scanf("%d",&x);
for(int i=;i<=k-;i++)
{
scanf("%d",&y);
union_set(x,y);
}
}
int sum=;
for(int i=;i<=n-;i++)
{
if(find_set(i)==pa[])
sum++;
}
printf("%d\n",sum);
}
return ;
}

UVA - 1197 (简单并查集计数)的更多相关文章

  1. POJ 2524 (简单并查集) Ubiquitous Religions

    题意:有编号为1到n的学生,然后有m组调查,每组调查中有a和b,表示该两个学生有同样的宗教信仰,问最多有多少种不同的宗教信仰 简单并查集 //#define LOCAL #include <io ...

  2. poj1611 简单并查集

    The Suspects Time Limit: 1000MS   Memory Limit: 20000K Total Submissions: 32781   Accepted: 15902 De ...

  3. 1213 How Many Tables(简单并查集)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 简单并查集,统计单独成树的数量. 代码: #include <stdio.h> #i ...

  4. 【简单并查集】Farm Irrigation

    Farm Irrigation Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Tot ...

  5. ACM_“打老虎”的背后(简单并查集)

    “打老虎”的背后 Time Limit: 2000/1000ms (Java/Others) Problem Description: “习大大”自担任国家主席以来大力反腐倡廉,各地打击贪腐力度也逐步 ...

  6. Codeforces Round #582 (Div. 3) G. Path Queries (并查集计数)

    题意:给你带边权的树,有\(m\)次询问,每次询问有多少点对\((u,v)\)之间简单路径上的最大边权不超过\(q_i\). 题解:真的想不到用最小生成树来写啊.... 我们对边权排序,然后再对询问的 ...

  7. poj1988 简单并查集

    B - 叠叠乐 Crawling in process... Crawling failed Time Limit:2000MS     Memory Limit:30000KB     64bit ...

  8. poj 2524 Ubiquitous Religions 一简单并查集

    Ubiquitous Religions   Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 22389   Accepted ...

  9. ACM_城市交通线(简单并查集)

    城市交通线 Time Limit: 2000/1000ms (Java/Others) Problem Description: A国有n座城市,编号为1~n,这n个城市之间没有任何交通线路,所以不同 ...

随机推荐

  1. javascript之url转义escape()、encodeURI()和decodeURI(),ifram父子传参参数有中文时出现乱码

    ifram父子传参参数有中文时出现乱码,可先在父级页面用encodeURI转义,在到子页面用进行decodeURI()解码 我们可以知道:escape()除了 ASCII 字母.数字和特定的符号外,对 ...

  2. CNN中卷积过程中padding的使用

    1.podding='SAME'时,全0填充.     2.padding=“VALID”,不使用全0填充      

  3. BZOJ4602: [Sdoi2016]齿轮(并查集 启发式合并)

    题意 题目链接 Sol 和cc的一道题很像啊 对于初始的\(N\)个点,每加一条限制实际上就是合并了两个联通块. 那么我们预处理出\(val[i]\)表示的是\(i\)节点所在的联通块根节点转了\(1 ...

  4. Oracle 通过出生日期计算年龄

    方法一: SELECT TRUNC(months_between(sysdate, birth)/12) AS age from mytable 方法二: select TRUNC((to_char( ...

  5. 毕向东_Java基础视频教程第19天_IO流(18~19)

    第19天-18-IO流(流操作规律 - 1) 通过三个步骤来明确"流操作"的规律: 明确数据流的"源和目的" 源, 输入流: InputStream/Reade ...

  6. 将csv导出json格式

    将csv导出json格式 import os,csv,json cf = open('D:\OneDrive\\Tech\\Script\\Powershell_Script\\Uxin_work\\ ...

  7. Python初学者第十七天 函数(1)

    17day 函数 1.函数定义: 函数 是指将一组语句的集合通过一个名字(函数名)封装起来,想要执行这个函数,只需调用其函数名即可 2.函数的特性: a 减少重复代码 b 使程序变得可扩展 c 使程序 ...

  8. Python实例---简单购物车Demo

    简单购物车Demo # version: python3.2.5 # author: 'FTL1012' # time: 2017/12/7 09:16 product_list = ( ['Java ...

  9. Mysql学习---Python操作Mysql 1231

    安装PyMysql 安装PyMysql:Py3默认自带pip3安装,Py2默认无pip命令 cmd进入PyCharm的安装目录完成安装 pip3 install pymysql 安装完成的位置:E:\ ...

  10. Linux kill/pkill/killall命令详解

    kill kill(terminate a process)命令用来终止指定的进程, 对于一个后台进程就须用kill命令来终止,我们就需要先使用ps/pidof/pstree/top等工具获取进程PI ...