https://leetcode.com/problems/count-numbers-with-unique-digits/

给定一个n,计算[0,10^n]中十进制中每一位都不相同的数的数目。

class Solution{
public:
int countNumbersWithUniqueDigits(int n){
int res=;
int wei = min(, n);
for(int i=wei; i>; i--){
int tmp = ;
for(int j=i-; j>; j--)
tmp *= -i+j+;
res+=tmp;
}
return res+;
}
};

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