package com.bbguoxue.poetry.util;
import java.security.SecureRandom; import javax.crypto.Cipher;
import javax.crypto.KeyGenerator;
import javax.crypto.SecretKey;
import javax.crypto.spec.SecretKeySpec;
/**
* AES加密器
* @author padnans
*
*/
public class AESEncryptor { /**
* AES加密
*/
public static String encrypt(String seed, String cleartext) throws Exception {
byte[] rawKey = getRawKey(seed.getBytes());
byte[] result = encrypt(rawKey, cleartext.getBytes());
return toHex(result);
} /**
* AES解密
*/
public static String decrypt(String seed, String encrypted) throws Exception {
byte[] rawKey = getRawKey(seed.getBytes());
byte[] enc = toByte(encrypted);
byte[] result = decrypt(rawKey, enc);
return new String(result);
} private static byte[] getRawKey(byte[] seed) throws Exception {
KeyGenerator kgen = KeyGenerator.getInstance("AES");
SecureRandom sr = SecureRandom.getInstance("SHA1PRNG", "Crypto");
sr.setSeed(seed);
kgen.init(128, sr); // 192 and 256 bits may not be available
SecretKey skey = kgen.generateKey();
byte[] raw = skey.getEncoded();
return raw;
} private static byte[] encrypt(byte[] raw, byte[] clear) throws Exception {
SecretKeySpec skeySpec = new SecretKeySpec(raw, "AES");
Cipher cipher = Cipher.getInstance("AES");
cipher.init(Cipher.ENCRYPT_MODE, skeySpec);
byte[] encrypted = cipher.doFinal(clear);
return encrypted;
} private static byte[] decrypt(byte[] raw, byte[] encrypted) throws Exception {
SecretKeySpec skeySpec = new SecretKeySpec(raw, "AES");
Cipher cipher = Cipher.getInstance("AES");
cipher.init(Cipher.DECRYPT_MODE, skeySpec);
byte[] decrypted = cipher.doFinal(encrypted);
return decrypted;
} public static String toHex(String txt) {
return toHex(txt.getBytes());
}
public static String fromHex(String hex) {
return new String(toByte(hex));
} public static byte[] toByte(String hexString) {
int len = hexString.length()/2;
byte[] result = new byte[len];
for (int i = 0; i < len; i++)
result[i] = Integer.valueOf(hexString.substring(2*i, 2*i+2), 16).byteValue();
return result;
} public static String toHex(byte[] buf) {
if (buf == null)
return "";
StringBuffer result = new StringBuffer(2*buf.length);
for (int i = 0; i < buf.length; i++) {
appendHex(result, buf[i]);
}
return result.toString();
}
private final static String HEX = "0123456789ABCDEF";
private static void appendHex(StringBuffer sb, byte b) {
sb.append(HEX.charAt((b>>4)&0x0f)).append(HEX.charAt(b&0x0f));
}
}

  上部分代码很多地方有,

红色那行是关键 很多地方代码只是:SecureRandom sr = SecureRandom.getInstance("SHA1PRNG");

android AES 部分机器javax.crypto.BadPaddingException: pad block corrupted的更多相关文章

  1. 左右 android AES 所述机器的一部分 javax.crypto.BadPaddingException: pad block corrupted

    好多人 android 使用上述 AES 显现 javax.crypto.BadPaddingException: pad block corrupted 下面的代码发布没问题,比较自己.不解释! p ...

  2. android 上AES解密是报错javax.crypto.BadPaddingException: pad block corrupted

    网上看到两种方法: 1.SecretKeySpec skeySpec = new SecretKeySpec(getRawKey(key), "AES"); private sta ...

  3. 关于javax.crypto.BadPaddingException: Blocktype错误的几种解决方法

    此文章转载自:http://www.myexception.cn/mobile/1259076.html 关于javax.crypto.BadPaddingException: Blocktype异常 ...

  4. javax.crypto.BadPaddingException: Given final block not properly padded解决方案

    解密的时候报错: javax.crypto.BadPaddingException:   Given   final   block   not   properly   padded 该异常是在解密 ...

  5. exception javax.crypto.BadPaddingException: Given final block not properly padded

      exception javax.crypto.BadPaddingException: Given final block not properly padded CreationTime--20 ...

  6. javax.crypto.BadPaddingException: Given final block not properly padded 解决方法

    下面的 Des 加密解密代码,在加密时正常,但是在解密是抛出错误: javax.crypto.BadPaddingException: Given final block not properly p ...

  7. javax.crypto.BadPaddingException: Given final block not properly padded

    一.报错 写了一个加密方法,在Windows上运行没有问题,在Linux上运行时提示如下错误: javax.crypto.BadPaddingException: Given final block ...

  8. java rsa 解密报:javax.crypto.BadPaddingException: Decryption error

    Exception in thread "main" javax.crypto.BadPaddingException: Decryption error    at sun.se ...

  9. android 开发解密时出现pad block corrupted 错误

    情景:在虚拟机上运行正常的,但是到我的真机上就解密失败,出现pad block corrupted  ,据说是版本原因:我机器是小米3 最新版的android  4.2 出现问题的代码: privat ...

随机推荐

  1. Regional Changchun Online--Alisha’s Party

    Alisha's Party Time Limit: 3000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) ...

  2. Hibernate高级查询QBC条件设置——Restrictions用法 引自:http://www.cnblogs.com/evon168/archive/2010/10/29/1863059.html

    方法说明 方法 说明 Restrictions.eq = Restrictions.allEq 利用Map来进行多个等于的限制 Restrictions.gt > Restrictions.ge ...

  3. Redis附加功能之键过期功能

    一.键过期功能的相关命令 二.设置生存时间 Redis 提供了两个命令来设置键的生存时间(TTL,time to live),它们分别是: 如果给定的键不存在,那么 EXPIRE 和 PEXPIRE ...

  4. linux包转发开发

    28号晚上接到这个任务的, 看了点epoll, 29号上午安装Ubuntu 12.10的G++, 开始把内网的vm虚拟机文件, 复制到外网, 重新建立一个虚拟机再更新, 最后外网也没能安装得了g++. ...

  5. 剑指Offer:面试题12——打印1到最大的n位数(java实现)

    问题描述: 输入数字n,按顺序打印出从1到最大的n位十进制数,比如输入3,则打印出1,2,3一直到最大的3位数即999. 思路1:最简单的想法就是先找出最大的n位数,然后循环打印即可. public ...

  6. VS error retrieving information from user datastore

    搭建好VS2005+PB6.0的开发环境后,新建MFC智能设备应用程序工程出错,错误信息如下: error retrieving information from user datastore 很奇怪 ...

  7. git克隆项目到一个非空目录

    这只是记录: 1. 进入非空目录,假设是 /workdir/proj1 2. git clone --no-checkout https://git.oschina.net/NextApp/platf ...

  8. 慕课网-安卓工程师初养成-4-9 Java循环语句之 for

    来源:http://www.imooc.com/code/1425 Java 的循环结构中除了 while 和 do...while 外,还有 for 循环,三种循环可以相互替换. 语法: 执行过程: ...

  9. 慕课网-安卓工程师初养成-3-6 Java中的逻辑运算符

    来源: http://www.imooc.com/code/1301 逻辑运算符主要用于进行逻辑运算.Java 中常用的逻辑运算符如下表所示: 我们可以从“投票选举”的角度理解逻辑运算符: 1. 与: ...

  10. c# 清空txt文本文件的值

    FileStream fs1 = null; try { fs1 = new FileStream(@"C:\db.txt", FileMode.Truncate, FileAcc ...