【解决方案】cvc-complex-type.2.4.a: Invalid content was found starting with element 'init-param'. One of '{"http://java.sun.com/xml/ns/javaee":run-as, "http://java.sun.com/xml/ns/javaee":security-role-r

【JAVA错误】

cvc-complex-type.2.4.a: Invalid content was found starting with element 'init-param'. One of '{"http://java.sun.com/xml/ns/javaee":run-as,   "http://java.sun.com/xml/ns/javaee":security-role-r

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【错误源码】

在springmvc 配置过程中，配置web.xml 中报出异常：

异常代码如下：

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
    http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <display-name></display-name>
    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>
    <!-- 配置springmvc核心控制器 -->
    <servlet>
        <servlet-name>springmvc</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <!-- 再启动web容器的时候，实例化servlet对象 -->
        <load-on-startup>1</load-on-startup>
        <init-param>
            <param-name>configLocation</param-name>
            <param-value>classpath:springmvc.xml</param-value>
        </init-param>
    </servlet>
    <servlet-mapping>
        <servlet-name>springmvc</servlet-name>
        <url-pattern>*.do</url-pattern>
    </servlet-mapping>
</web-app>

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【解决方案】

错误点：

     <load-on-startup>1</load-on-startup>
        <init-param>
            <param-name>configLocation</param-name>
            <param-value>classpath:springmvc.xml</param-value>
        </init-param>    

将代码中

<load-on-startup>1</load-on-startup>

放在<init-param>标签之下即可：

<init-param>
       <param-name>configLocation</param-name>
       <param-value>classpath:springmvc.xml</param-value>
 </init-param>  
<!-- 关键点 -->
 <load-on-startup>1</load-on-startup>