Problem A CodeForces 560A
Description
A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of each value. Such sum is called unfortunate. Gerald wondered: what is the minimumunfortunate sum?
Input
The first line contains number n (1 ≤ n ≤ 1000) — the number of values of the banknotes that used in Geraldion.
The second line contains n distinct space-separated numbers a1, a2, ..., an (1 ≤ ai ≤ 106) — the values of the banknotes.
Output
Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print - 1.
Sample Input
5
1 2 3 4 5
-1
分析:
这题只用两种可能,就是输入有1与无1,有1时就找不到sum,所以输出-1;无1时有最小sum为1,即输出为1.
#include <iostream>
#include <cstdio>
using namespace std;
int main()
{
int n,i;
while(scanf("%d",&n)==1&&n)
{
int f=0;
for(i=0;i<n;i++)
{
int x;
scanf("%d",&x);
if(x==1)
f=1;
}
if(!f)
printf("1\n");
else
printf("-1\n");
}
return 0;
}
Problem A CodeForces 560A的更多相关文章
- Problem - D - Codeforces Fix a Tree
Problem - D - Codeforces Fix a Tree 看完第一名的代码,顿然醒悟... 我可以把所有单独的点全部当成线,那么只有线和环. 如果全是线的话,直接线的条数-1,便是操作 ...
- Codeforces Round #439 (Div. 2) Problem E (Codeforces 869E) - 暴力 - 随机化 - 二维树状数组 - 差分
Adieu l'ami. Koyomi is helping Oshino, an acquaintance of his, to take care of an open space around ...
- Codeforces Round #439 (Div. 2) Problem C (Codeforces 869C) - 组合数学
— This is not playing but duty as allies of justice, Nii-chan! — Not allies but justice itself, Onii ...
- Codeforces Round #439 (Div. 2) Problem B (Codeforces 869B)
Even if the world is full of counterfeits, I still regard it as wonderful. Pile up herbs and incense ...
- Codeforces Round #439 (Div. 2) Problem A (Codeforces 869A) - 暴力
Rock... Paper! After Karen have found the deterministic winning (losing?) strategy for rock-paper-sc ...
- Codeforces Round #424 (Div. 2, rated, based on VK Cup Finals) Problem F (Codeforces 831F) - 数论 - 暴力
题目传送门 传送门I 传送门II 传送门III 题目大意 求一个满足$d\sum_{i = 1}^{n} \left \lceil \frac{a_i}{d} \right \rceil - \sum ...
- Codeforces Round #424 (Div. 2, rated, based on VK Cup Finals) Problem D (Codeforces 831D) - 贪心 - 二分答案 - 动态规划
There are n people and k keys on a straight line. Every person wants to get to the office which is l ...
- Codeforces Round #424 (Div. 2, rated, based on VK Cup Finals) Problem E (Codeforces 831E) - 线段树 - 树状数组
Vasily has a deck of cards consisting of n cards. There is an integer on each of the cards, this int ...
- Codeforces Round #424 (Div. 2, rated, based on VK Cup Finals) Problem C (Codeforces 831C) - 暴力 - 二分法
Polycarp watched TV-show where k jury members one by one rated a participant by adding him a certain ...
随机推荐
- PLSQL Developer连接远程Oracle方法(非安装客户端)
Oracle比较麻烦,通常需要安装oracle的客户端才能实现.通过instantclient可以比较简单的连接远程的Oracle. 1.新建目录D:\Oracle_Cleint用于存放相关文件,新建 ...
- 【linux命令】:查看系统运行状态,命令top 【转载】
原文:http://www.cnblogs.com/ggjucheng/archive/2012/01/08/2316399.html 简介 top命令是Linux下常用的性能分析工具,能够实时显示系 ...
- JQuery基础汇总
1. 对象获取与赋值::$("#obj").val("Hello World!"); 2. 对象的显示与隐藏:$("#obj").show( ...
- 小韦系统装工行网银U盾驱动的方法
小韦系统装工行网银U盾驱动的方法 拷贝文件.bat @echo 开始注册echo n|copy /-y scarddlg.dll %windir%\system32\echo n|copy /-y w ...
- typedef void (*funcptr)(void)
定义一个函数指针类型.比如你有三个函数:void hello(void) { printf("你好!"); }void bye(void) { printf("再见!&q ...
- WebDriver 在使用 CSS Selector 与 XPath 在查找元素时如何取舍
开发在做Web系统时,用的是css div划分层,使用jQuery 选取元素.
- phonegap插件加载与使用
有朋友问能不能在CanTK和AppBuilder开发的APP里发送UDP数据,HTML5里只能用HTTPS/HTTP/WebSocket几种通讯方式,要使用UDP需要通过phonegap打包成APK等 ...
- 理解Cookie和Session机制
转载: 理解Cookie和Session机制 会话(Session)跟踪是Web程序中常用的技术,用来跟踪用户的整个会话.常用的会话跟踪技术是Cookie与Session.Cookie通过在客户端记录 ...
- python 使用*args 和**kwargs
def fun_var_args(farg, *args): print "arg:", farg for value in args: print "another a ...
- WPF:ListView数据绑定及Style
DrugRecordsWin.xaml <ListView Grid.Row="4" Grid.Column="1" Name="list_Dr ...