python子类分配

原问题是将左边样式变成右边样式：

即有父类和子类，父类包括多个子类，怎样将子类匹配到父类下面的问题

代码如下

 #!/usr/bin/python3.4
 # -*- coding: utf-8 -*-

 arr1 = ["S01","S01","S01","S02","S03","S04","S04"]
 arr2 = ["G0001","G0002","G0003","G0004","G0003","G0004","G0005"]
 # 用来存放父类
 father = []
 # 放入第一个单方便后面循环计算
 father.append(arr1[0])
 # 子类
 son = []
 # 临时数组
 temp = []

 for i in range(0,len(arr1)):
     # 如果father里面存在，就跳过
     # 把子类存入临时数组
     if arr1[i] in father:
         temp.append(arr2[i])
         pass
     # 如果father里面不存在
     # 释放临时数组
     else:
         son.append(temp)
         temp = []
         father.append(arr1[i])
         temp.append(arr2[i])
 # 将最后一次循环的temp放入son
 son.append(temp)
 print(father)
 print(son)

运行效果：