android MotionEvent 获取长按压时间长

思路：

1.记录ACTION_DOWN的aX, aY坐标；

2.在ACTION_MOVE判断是否移动，移动则取消记录时间，没移动就记录；

3.记录时间，按下坐标，移动坐标分别显示在TextView aa, bb, cc；

//声明

 public class MainActivity extends ActionBarActivity {
     private static TextView aa, bb, cc;
     private float atime;
     private float aX, aY;
     private boolean mPressBreak = false;

//指定

 aa = (TextView) findViewById(R.id.textView1);
 bb = (TextView) findViewById(R.id.textView2);
 cc = (TextView) findViewById(R.id.textView3);

//获取按压时间长

 @Override
     public boolean onTouchEvent(MotionEvent event) {
         // TODO Auto-generated method stub
         super.onTouchEvent(event);
         String str = "";
         switch (event.getAction()) {
         case MotionEvent.ACTION_DOWN:
             aX = event.getX();
             aY = event.getY();
             str = String.valueOf(aX) + " , " + String.valueOf(aY);
             bb.setText(str);
             mPressBreak = false;
             break;
         case MotionEvent.ACTION_MOVE:

             atime = (event.getEventTime() - event.getDownTime()) / 1000;
             str = String.valueOf(event.getX()) + " , "
                     + String.valueOf(event.getY());
             if ((Math.abs((event.getX() - aX)) > 10)
                     || (Math.abs(event.getY() - aY) > 10)) {
                 atime = 0;
                 mPressBreak = true;
             }
             break;

         }

         if (!mPressBreak) {
             aa.setText(String.valueOf((int) (atime)));
             cc.setText(str);
         }

         return true;
     }