HW7.8

import java.util.ArrayList;
import java.util.Scanner;
public class Solution
{
public static void main(String[] args)
{
ArrayList<String> list = new ArrayList<>();
Scanner input = new Scanner(System.in);
System.out.print("Enter the count of points: ");
int pointCount = input.nextInt();
double[][] points = new double[pointCount][2];
System.out.print("Enter the points: ");
for(int i = 0; i < pointCount; i++)
for(int j = 0; j < 2; j++)
points[i][j] = input.nextDouble();
input.close();
double shortestDistance = distance(points[0][0], points[0][1], points[1][0], points[1][1]);
double currentDistance = shortestDistance;
for(int i = 0; i < points.length; i++)
for(int j = i + 1; j < points.length; j++)
{
currentDistance = distance(points[i][0], points[i][1], points[j][0], points[j][1]);
if(currentDistance < shortestDistance)
{
list.clear();
shortestDistance = currentDistance;
list.add("(" + points[i][0] + " " + points[i][1] + ") (" + points[j][0] + " " + points[j][1] + ")");
}
else if(currentDistance == shortestDistance)
{
list.add("(" + points[i][0] + " " + points[i][1] + ") (" + points[j][0] + " " + points[j][1] + ")");
}
}
System.out.println("The shortest distance is " + shortestDistance);
for(int i = 0; i < list.size(); i++)
System.out.println(list.get(i));
}
public static double distance(double x1, double y1, double x2, double y2)
{
double square = (x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1);
return Math.sqrt(square);
}
}
HW7.8的更多相关文章
- HW7.18
public class Solution { public static void main(String[] args) { int[][] m = {{1, 2}, {3, 4}, {5, 6} ...
- HW7.17
import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner i ...
- HW7.16
import java.util.Arrays; public class Solution { public static void main(String[] args) { int row = ...
- HW7.15
public class Solution { public static void main(String[] args) { double[][] set1 = {{1, 1}, {2, 2}, ...
- HW7.14
import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner i ...
- HW7.13
import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner i ...
- HW7.12
import java.util.Scanner; public class Solution { public static void main(String[] args) { double[] ...
- HW7.11
import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner i ...
- HW7.10
public class Solution { public static void main(String[] args) { int[][] array = new int[3][3]; for( ...
- HW7.9
import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner i ...
随机推荐
- uva 11143
#include<cstdio> #include<cstring> #include<algorithm> #define maxn 5100 #include& ...
- uva 10069
简单的dp 但是一个大数加法 套用了末位大牛的类模板 #include <cstdio> #include <cstring> #include <algorithm& ...
- 学习笔记:shared_ptr陷阱
条款1:不要把一个原生指针给多个shared_ptr管理 int* ptr = new int; shared_ptr<int> p1(ptr); shared_ptr<int> ...
- SQL Server CONVERT() 函数
http://www.w3school.com.cn/sql/func_convert.asp 定义和用法 CONVERT() 函数是把日期转换为新数据类型的通用函数. CONVERT() 函数可以用 ...
- POJ 1797 Heavy Transportation(Dijkstra)
http://poj.org/problem?id=1797 题意 :给出N个城市M条边,每条边都有容量值,求一条运输路线使城市1到N的运输量最大. 思路 :用dijkstra对松弛条件进行变形.解释 ...
- MyBatis-Spring 执行SQL语句的流程
1. 从SqlSessionDaoSupport开始 通常我们使用MyBatis会让自己的DAO继承SqlSessionDaoSupport,那么SqlSessionDaoSupport是如何运作的呢 ...
- !! Scrum之 流程和术语
!!Scrum之 流程和术语 http://www.cnblogs.com/zhoujg/archive/2009/07/15/1523680.html 以下将对一些术语进行简单介绍,以便大家现在开始 ...
- 【HDOJ】4363 Draw and paint
看题解解的.将着色方案映射为40*40*5*5*5*5*2个状态,40*40表示n*m,5*5*5*5表示上下左右相邻块的颜色,0表示未着色.2表示横切或者竖切.基本思路是记忆化搜索然后去重,关键点是 ...
- Java数据库增删改查
数据库为MySQL数据库,Oracle数据库类似: create database db_test;--创建数据库 ';--创建用户 grant all privileges on db_test.* ...
- grep 同时满足多个关键字和满足任意关键字
grep 同时满足多个关键字和满足任意关键字 ① grep -E "word1|word2|word3" file.txt 满足任意条件(word1.word2和word ...