hdu 1551 Cable master (二分法)
Cable master
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 1428 Accepted Submission(s): 522
To buy network cables, the Judging Committee has contacted a local network solutions provider with a request to sell for them a specified number of cables with equal lengths. The Judging Committee wants the cables to be as long as possible to sit contestants as far from each other as possible.
The Cable Master of the company was assigned to the task. He knows the length of each cable in the stock up to a centimeter, and he can cut them with a centimeter precision being told the length of the pieces he must cut. However, this time, the length is not known and the Cable Master is completely puzzled.
You are to help the Cable Master, by writing a program that will determine the maximal possible length of a cable piece that can be cut from the cables in the stock, to get the specified number of pieces.
The input is ended by line containing two 0's.
If it is not possible to cut the requested number of pieces each one being at least one centimeter long, then the output must contain the single number "0.00" (without quotes).
8.02
7.43
4.57
5.39
0 0
//187MS 320K 650 B G++
/* 题意:
给你n块木板,长为ai,要用这些木板分成k块等长的木板,问最长可为多长 二分法:
和之前某题一样的想法,就是计算出当长度为x时可得到的木板块数是否符合
然后几时二分的思想做。 */
#include<stdio.h>
#include<string.h>
double a[];
int n,k;
int fac(double x)
{
int cnt=;
for(int i=;i<n;i++)
cnt+=(int)(a[i]/x);
return cnt;
}
int main(void)
{
while(scanf("%d%d",&n,&k),n+k)
{
double l=;
double r=;
for(int i=;i<n;i++){
scanf("%lf",&a[i]);
r+=a[i];
}
r/=k;
while(r-l>=0.00001){
double mid=(r+l)/;
int m=fac(mid);
if(m>=k) l=mid;
else if(m<k) r=mid;
}
//printf("%d\n",fac(r));
printf("%.2lf\n",l);
}
return ;
}
hdu 1551 Cable master (二分法)的更多相关文章
- HDU 1551 Cable master
题解:很显然的二分检索,在算法艺术上看过原题,不过这里要注意精度: #include <cstdio> int n,m; ]; bool test(double x){ ,i; ;i< ...
- HDU 1551 Cable master【二分答案】
题意:给出n块木板,它们分别的高度,现在要把它们裁切成k块,问裁切成的最大的高度 二分答案,上限是这n块木板里面的最大值 然后每一个答案去判断一下是否满足能够裁切成k块 #include<ios ...
- POJ 1064 Cable master (二分法+精度控制)
Cable master Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 65358 Accepted: 13453 De ...
- Cable master 求电缆的最大长度(二分法)
Description Inhabitants of the Wonderland have decided to hold a regional programming contest. The J ...
- 二分法的应用:POJ1064 Cable master
/* POJ1064 Cable master 时间限制: 1000MS 内存限制: 10000K 提交总数: 58217 接受: 12146 描述 Wonderland的居民已经决定举办地区性编程比 ...
- Cable master--hdu1551(二分法)
Cable master Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tota ...
- poj1064 Cable master(二分)
Cable master 求电缆的最大长度(二分法) Description Inhabitants of the Wonderland have decided to hold a region ...
- POJ 1064 Cable master (二分)
题目链接: 传送门 Cable master Time Limit: 1000MS Memory Limit: 65536K 题目描述 有N条绳子,它们长度分别为Li.如果从它们中切割出K条长 ...
- [ACM] poj 1064 Cable master (二分查找)
Cable master Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 21071 Accepted: 4542 Des ...
随机推荐
- 记录表TABLE中 INDEX BY BINARY_INTEGER 的作用
type my_number_arr is table of number index by binary_integer; 其作用是,加了”index by binary_integer ”后,my ...
- 使用Jmeter性能测试,读取csv文件时的乱码问题
读取csv参数乱码问题 发送请求时参数通过CSV文件读取,发送请求后显示错误,把获取的参数通过在线urlencode转码器转码后发现是乱码.打开csv设值,编码格式选择的是UTF-8,打开参数文件后发 ...
- exa命令详解
exa 是 ls 文件列表命令现代化替代品. 官网:https://the.exa.website/ GitHub:https://github.com/ogham/exa 后续整理中……
- Redis在windows下安装过程(转)
(转)原文:http://www.cnblogs.com/M-LittleBird/p/5902850.html 要使redis在PHP下运行, 需在PHP文件下的ext扩展文件夹中添加扩展文件 ph ...
- #Python编程从入门到实践#第三章笔记
列表简介 1.什么是列表 列表:由一系列按也顶顺序排列的元素组成.元素之间可以没有任何关系. 列表:用方括号[]表示,并用逗号分隔其中元素.名称一般为复数 2.访问元素 (1)列表是有序集合 ...
- Python全栈day 01
Python全栈day 01 一.计算机认识 用户 软件,类似微信.QQ.游戏等应用程序,由程序员编写,在系统中运行,完成各种活动,方便人们使用. 操作系统,主要分为windows系统.Linux系统 ...
- iOS-cell的封装和重用
一.通过xib描述cell---(cell的高度一致,cell里面控件布局基本一样): 1.(M) 创建模型: -------------------------------------------- ...
- PAT Basic 1057
1057 数零壹 给定一串长度不超过 105 的字符串,本题要求你将其中所有英文字母的序号(字母 a-z 对应序号 1-26,不分大小写)相加,得到整数 N,然后再分析一下 N 的二进制表示中有 ...
- 笔记-python-functool-@wraps
笔记-python-functool-@wraps 1. wraps 经常看到@wraps装饰器,查阅文档学习一下 在了解它之前,先了解一下partial和updata_wrapper这两个 ...
- 笔记-python-多环境-virtualenv
笔记-python-多环境-virtualenv 1. 多环境 在开发Python应用程序的时候,系统安装的Python3只有一个版本:3.6.4,所有第三方的包都会被pip安装到Pytho ...