Scala的Json序列化

import java.util.TimeZone
import com.fasterxml.jackson.databind.{DeserializationFeature, ObjectMapper}
import com.fasterxml.jackson.datatype.joda.JodaModule
import com.fasterxml.jackson.module.scala.DefaultScalaModule
import com.fasterxml.jackson.module.scala.experimental.ScalaObjectMapper

object JsonUtil {
  val mapper = new ObjectMapper() with ScalaObjectMapper
  mapper.setTimeZone(TimeZone.getTimeZone("Asia/Shanghai"))
  mapper.registerModule(DefaultScalaModule)
  mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false)
  mapper.registerModule(new JodaModule)

  def toJson(value: Map[Symbol, Any]): String = {
    toJson(value map { case (k, v) => k.name -> v })
  }

  def toJson(value: Any): String = {
    mapper.writeValueAsString(value)
  }

  def toMap[V](json: String)(implicit m: Manifest[V]) = fromJson[Map[String, V]](json)

  def fromJson[T](json: String)(implicit m: Manifest[T]): T = {
    mapper.readValue[T](json)
  }
}

build.sbt 中需要引用依赖

libraryDependencies += "com.fasterxml.jackson.module" % "jackson-module-scala_2.11" % "2.8.4"

libraryDependencies += "com.fasterxml.jackson.core" % "jackson-databind" % "2.5.4"

libraryDependencies += "com.fasterxml.jackson.datatype" % "jackson-datatype-joda" % "2.8.4"

//转json
val json = JsonUtil.toJson(obj)

//解json,这里T是具体类型
val obj = JsonUtil.fromJson[T](json)