Given a linked list, determine if it has a cycle in it.

Follow up:
Can you solve it without using extra space?

思路:维护两个指针,一快一慢,判断两个指针能否相遇。

 class Solution {
public:
bool hasCycle(ListNode *head) {
if (head == NULL) return false;
ListNode *slow = head;
if (head->next == NULL) return false;
ListNode *fast = head->next;
while (slow != fast)
{
if (slow != NULL)
slow = slow->next;
if (fast != NULL)
fast = fast->next;
if (fast != NULL)
fast = fast->next;
}
return slow != NULL;
}
};

Linked List Cycle - LeetCode的更多相关文章

  1. 141. Linked List Cycle - LeetCode

    Question 141. Linked List Cycle Solution 题目大意:给一个链表,判断是否存在循环,最好不要使用额外空间 思路:定义一个假节点fakeNext,遍历这个链表,判断 ...

  2. Linked List Cycle——LeetCode

    Given a linked list, determine if it has a cycle in it. Follow up:Can you solve it without using ext ...

  3. Linked List Cycle leetcode II java (寻找链表环的入口)

    题目: Given a linked list, return the node where the cycle begins. If there is no cycle, return null. ...

  4. Linked List Cycle leetcode java (链表检测环)

    题目: Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without usin ...

  5. [LeetCode] Linked List Cycle II 单链表中的环之二

    Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Foll ...

  6. [LeetCode] Linked List Cycle 单链表中的环

    Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using ex ...

  7. Java for LeetCode 142 Linked List Cycle II

    Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Foll ...

  8. LeetCode解题报告:Linked List Cycle && Linked List Cycle II

    LeetCode解题报告:Linked List Cycle && Linked List Cycle II 1题目 Linked List Cycle Given a linked ...

  9. [LeetCode] 141&142 Linked List Cycle I & II

    Problem: Given a linked list, determine if it has a cycle in it. Follow up:Can you solve it without ...

随机推荐

  1. C++ 11 从C++ primer第五版的学习笔记

    1. auto (page107) auto 推断会忽略const   const int ci = i, & cr = ci; auto b = ci; // b is an int (to ...

  2. Codeforces 653G Move by Prime 组合数学

    题意: 有一个长度为\(n\)的正整数序列\(a\),有这样一种操作: 每次可以选序列中的某一个数乘上或除以某一个素数. 求对于每一个子序列使其所有元素相等的最少操作次数之和. 分析: 因为两个素数之 ...

  3. ActiveMQ初步学习

    本文主要参考张丰哲大神的简书文章,链接 https://www.jianshu.com/p/ecdc6eab554c JMS,即Java Message Service,通过面向消息中间件(MOM:M ...

  4. k8s与CICD--借助scp插件实现非容器项目的部署

    一直没有时间完成drone系列文章.drone-wechat插件实现了一半,由于企业微信token申请比较麻烦,所以也没有进展.今天抽出时间,研究了一下scp插件,主要目的是实现非容器项目的部署.其实 ...

  5. 201621123034 《Java程序设计》第1周学习总结

    1. 本周学习总结 知道了java的用途有安卓手机应用,企业服务器后端,java web.学到了新概念:类.HelloWorld.java 中 HelloWorld 是主文件名,区分 .java和 . ...

  6. C++字符串高效查找替换,有空分析分析

    void CWebTransfer::Substitute(char *pInput, char *pOutput, char *pSrc, char *pDst) { char *pi, *po, ...

  7. LAMP第一部分安装mysql -apache -php

    1. 安装mysqlcd /usr/local/src/ 免安装编译二进制的包wget http://syslab.comsenz.com/downloads/linux/mysql-5.1.40-l ...

  8. hibernate级联查询映射的两种方式

    Hibernate主要支持两种查询方式:HQL查询和Criteria查询.前者应用较为广发,后者也只是调用封装好的接口. 现在有一个问题,就是实现多表连接查询,且查询结果集不与任何一个实体类对应,怎么 ...

  9. BZOJ 1787: [Ahoi2008]Meet 紧急集合(lca+贪心)

    [Ahoi2008]Meet 紧急集合 Description Input Output Sample Input 6 4 1 2 2 3 2 4 4 5 5 6 4 5 6 6 3 1 2 4 4 ...

  10. 【bzoj4966】总统选举 随机化+线段树

    题目描述 黑恶势力的反攻计划被小C成功摧毁,黑恶势力只好投降.秋之国的人民解放了,举国欢庆.此时,原秋之国总统因没能守护好国土,申请辞职,并请秋之国人民的大救星小C钦定下一任.作为一名民主人士,小C决 ...