[React Router v4] Intercept Route Changes
If a user has entered some input, or the current Route is in a “dirty” state and we want to confirm that data will be lost, React Router v4 provides a Prompt component to interrupt the Route transition and ask the user a question.
For example we need to way to tell user if he leaves the page, data will lost.
We can use 'Prompt' component from router lib.
import React from 'react';
import {Link, Route, Prompt} from 'react-router-dom'; const Home = () => (<h1>Home</h1>);
class Form extends React.Component {
state = {
dirty: false
}; setDirty = () => {
this.setState((preState, props) => {
return {
dirty: true
}
})
}; render(){
return(
<div>
<h1>Form</h1>
<input type="text" onInput={this.setDirty}/>
<Prompt
when={this.state.dirty}
message="Date will be lost"
></Prompt>
</div>
);
}
} const Guards = () => (
<div>
<Link to="/guards/home">Home</Link>
<Link to="/guards/form">Form</Link> <Route path="/guards/home" component={Home}></Route>
<Route path="/guards/form"
component={Form}
></Route>
</div>
); export default Guards;
[React Router v4] Intercept Route Changes的更多相关文章
- [React Router v4] Conditionally Render a Route with the Switch Component
We often want to render a Route conditionally within our application. In React Router v4, the Route ...
- [React Router v4] Render Multiple Components for the Same Route
React Router v4 allows us to render Routes as components wherever we like in our components. This ca ...
- [Web 前端] React Router v4 入坑指南
cp from : https://www.jianshu.com/p/6a45e2dfc9d9 万恶的根源 距离React Router v4 正式发布也已经过去三个月了,这周把一个React的架子 ...
- React Router V4发布
React Router V4 正式版发布,该版本相较于前面三个版本有根本性变化,遵循 Just Component 的 API 设计理念. 本次升级的主要变更有: 声明式 Declarative 可 ...
- [React Router v4] Redirect to Another Page
Overriding a browser's current location without breaking the back button or causing an infinite redi ...
- [React Router v4] Render Catch-All Routes with the Switch Component
There are many cases where we will need a catch-all route in our web applications. This can include ...
- [React Router v4] Render Nested Routes
With React Router v4 the entire library is built as a series of React components. That means that cr ...
- [React Router v4] Parse Query Parameters
React Router v4 ignores query parameters entirely. That means that it is up to you to parse them so ...
- [React Router v4] Use Regular Expressions with Routes
We can use regular expressions to more precisely define the paths to our routes in React Router v4. ...
随机推荐
- 今天发现里一个非常好用的Listbox自绘类,带不同文字字体和图片,觉得很有必要记下来
代码简写 MyListBox.h class CUseListBox : public CListBox { typedef struct _ListBox_Data { CString strApp ...
- mysql-5.7.19-winx64服务无法启动解决方案
解压mysql压缩包时没有data文件夹,不要手动创建,在cmd下直接运行命令: mysqld –initialize-insecure,data文件夹会自动生成,注意单词千万不要拼错,不要写成–in ...
- ASP.NET MVC案例教程(基于ASP.NET MVC beta)——第一篇:准备工作
摘要 本文将简要介绍这个文章系列的目的.形式及大体内容.并且完成开始学习这个系列前所必要的准备工作. 前言 ASP.NET MVC作为微软官方的MVC解决方案,推出有一段时间了.可 ...
- Hibernate3.5.4---java application的xml和annotation环境搭建(hibernate.cfg.xml配置文件说明,映射文件Student.hbm.xml说明
http://blog.csdn.net/centre10/article/details/6050466 来自于:http://blog.csdn.net/centre10/article/deta ...
- oled的一套stm32实验1
详细的oled介绍:http://blog.sina.com.cn/s/blog_57ad1bd20102wtq8.html 整理自:https://www.cnblogs.com/wp2312139 ...
- ZOJ 2723 Semi-Prime ||ZOJ 2060 Fibonacci Again 水水水!
两题水题: 1.如果一个数能被分解为两个素数的乘积,则称为Semi-Prime,给你一个数,让你判断是不是Semi-Prime数. 2.定义F(0) = 7, F(1) = 11, F(n) = F( ...
- SQL Server 中计算农历
1.建一表,放初始化资料 因为农历的日期,是由天文学家推算出来的,到现在只有到2049年的,以后的有了还可以加入! CREATE TABLE SolarData ( yearId int no ...
- C语言结构体的字节对齐原则
为什么要对齐? 现代计算机中内存空间都是按照byte划分的,从理论上讲似乎对任何类型的变量的访问可以从任何地址开始,但实际情况是在访问特定类型变量的时候经常在特 定的内存地址访问,这就需要各种类型数据 ...
- python3中numpy函数的argsort()
摘自:https://www.cnblogs.com/yushuo1990/p/5880041.html argsort函数argsort函数返回的是数组值从小到大的索引值 Examples----- ...
- 20、在PC上测试虚拟驱动vivi
在Ubuntu上测试 准备工作:安装xawtv(是一个应用程序,用来在Ubuntu上捕获摄像头数据并显示)sudo apt-get install xawtv 源码xawtv-3.95.tar.gz: ...