POJ 2387 Til the Cows Come Home(最短路模板)
题目链接:http://poj.org/problem?id=2387
题意:有n个城市点,m条边,求n到1的最短路径。n<=1000; m<=2000
就是一个标准的最短路模板。
#include<iostream>
#include<algorithm>
#include<cstring>
#include<vector>
#include<queue> using namespace std;
const int maxn = ;
const int INF = 0x3f3f3f3f3f;
int n, m;
struct node{
int to, cost;
node() {}
node(int a, int b) :to(a), cost(b) {}
};
vector<node> e[maxn];
int vis[maxn], f[maxn], dis[maxn];
void SPFA(int s)
{
for (int i = ; i < maxn; i++) {
vis[i] = ; f[i] = ;
dis[i] = INF;
}
dis[s] = ;
vis[s] = ; f[s]++;
queue<int>Q;
Q.push(s);
while (!Q.empty()) {
int t = Q.front(); Q.pop();
vis[t] = ;
for (int i = ; i < e[t].size(); i++) {
int tmp = e[t][i].to;
if (dis[tmp] > dis[t] + e[t][i].cost) {
dis[tmp] = dis[t] + e[t][i].cost;
if (!vis[tmp]) {
vis[tmp] = ;
Q.push(tmp);
if (++f[tmp] > n)return;
}
}
}
}
return;
}
int main()
{
ios::sync_with_stdio(false);
while (cin >> m >> n) {
for (int a, b, c, i = ; i <= m; i++) {
cin >> a >> b >> c;
e[a].push_back(node(b, c));
e[b].push_back(node(a, c));
}
SPFA();
cout << dis[n] << endl;
}
return ;
}
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