leetcode Combination Sum python
Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from C unlimited number of times. Note:
All numbers (including target) will be positive integers.
Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
The solution set must not contain duplicate combinations.
For example, given candidate set 2,3,6,7 and target 7,
A solution set is:
[7]
[2, 2, 3] class Solution(object):
def combinationSum(self, candidates, target):
"""
:type candidates: List[int]
:type target: int
:rtype: List[List[int]]
"""
candidates.sort()
self.ret=[] self.dfs(candidates,target,0,[])
return self.ret
def dfs(self,candidates,target,start,valuelist):
intlen=len(candidates)
if target==0:
return self.ret.append(valuelist)
for i in range(start,intlen):
if target < candidates[i]:
return
self.dfs(candidates,target-candidates[i],i,valuelist+[candidates[i]])
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