hdu 1556 Color the ball (技巧 || 线段树)

Color the ball
Time Limit: 9000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 28415    Accepted Submission(s): 13851

Problem Description
N个气球排成一排，从左到右依次编号为1,2,3....N.每次给定2个整数a b(a <= b),lele便为骑上他的“小飞鸽"牌电动车从气球a开始到气球b依次给每个气球涂一次颜色。但是N次以后lele已经忘记了第I个气球已经涂过几次颜色了，你能帮他算出每个气球被涂过几次颜色吗？
 

Input
每个测试实例第一行为一个整数N,(N <= 100000).接下来的N行，每行包括2个整数a b(1 <= a <= b <= N)。
当N = 0，输入结束。
 

Output
每个测试实例输出一行，包括N个整数，第I个数代表第I个气球总共被涂色的次数。
 

Sample Input
3
1 1
2 2
3 3
3
1 1
1 2
1 3
0
 

Sample Output
1 1 1
3 2 1

C/C++（线段树）：

 #include <map>
 #include <queue>
 #include <cmath>
 #include <vector>
 #include <string>
 #include <cstdio>
 #include <cstring>
 #include <climits>
 #include <iostream>
 #include <algorithm>
 #define INF 0x3f3f3f3f
 using namespace std;
 const int MAX = 5e5 + ;

 int n, a, b;

 struct nod
 {
     int L, R, val;
 }node[MAX];

 void build(int d, int l, int r)
 {
     node[d].L = l, node[d].R = r, node[d].val = ;
     if (l == r) return;
     int mid = (l + r) >> ;
     build(d << , l, mid);
     build((d << ) + , mid + , r);
 }

 void update(int d, int l, int r)
 {
     if (node[d].L == l && node[d].R == r)
     {
         node[d].val ++;
         return;
     }
     if (node[d].L == node[d].R) return;
     int mid = (node[d].L + node[d].R) >> ;
     if (r <= mid)
         update(d << , l, r);
     else if (mid < l)
         update((d << ) + , l, r);
     else
     {
         update(d << , l, mid);
         update((d << ) + , mid + , r);
     }
 }

 int query(int d, int l, int r)
 {
     if (node[d].L == l && node[d].R == r) return node[d].val;
     if (node[d].L == node[d].R) return ;
     int mid = (node[d].L + node[d].R) >> ;
     if (r <= mid)
         return node[d].val + query(d << , l, r);
     else if (mid < l)
         return node[d].val + query((d << ) + , l, r);
     else
         return node[d].val + query(d << , l, mid) + query((d << ) + , mid + , r);
 }

 int main()
 {
     while (scanf("%d", &n), n)
     {
         build(, , n);
         for (int i = ; i < n; ++ i)
         {
             scanf("%d%d", &a, &b);
             update(, a, b);
         }
         for (int i = ; i < n; ++ i)
             printf("%d ", query(, i, i));
         printf("%d\n", query(, n, n));
     }
     return ;
 }

C/C++（技巧）：

 #include <map>
 #include <queue>
 #include <cmath>
 #include <vector>
 #include <string>
 #include <cstdio>
 #include <cstring>
 #include <climits>
 #include <iostream>
 #include <algorithm>
 #define INF 0x3f3f3f3f
 using namespace std;
 const int MAX = 1e5 + ;

 int n, a, b;

 int main()
 {
     while (scanf("%d", &n), n)
     {
         int num[MAX] = {}, m = ;
         for (int i = ; i <= n; ++ i)
         {
             scanf("%d%d", &a, &b);
             num[a] ++, num[b + ] --;
         }
         for (int i = ; i < n; ++ i)
         {
             m += num[i];
             printf("%d ", m);
         }
         printf("%d\n", m + num[n]);
     }
     return ;
 }