oracle中利用trigger,sequence自动生成ID

http://zhanghong.iteye.com/blog/865937

1. 首先创建数据库表

SQL> create table customer(

2  id number(8) not null primary key,

3  name varchar2(20),

4  age number(3),

5  gender varchar2(8)

6  );

2. 创建Sequence：

create sequence customer_SEQUENCE start with 6 increment by 1

3.创建Trigger:

create or replace trigger customer_trgger

before insert or update on customer

for each row

begin

select customer_SEQUENCE.nextval into :NEW.userID from dual;

end;

在插入数据的时候就不用提供id了。

SQL> insert into customer(name,age,gender) values('abc',33,'male');

1 row created.