【Codecraft-18 and Codeforces Round #458 (Div. 1 + Div. 2, combined) A】 Perfect Squares
【链接】 我是链接,点我呀:)
【题意】
在这里输入题意
【题解】
N*1000暴力就好
【代码】
#include <bits/stdc++.h>
using namespace std;
const int N = 1e3;
int n,a[N+10];
bool is(int x){
for (int i = 0;i <= 1000;i++)
if (i*i==x) return true;
return false;
}
int main(){
#ifdef LOCAL_DEFINE
freopen("rush_in.txt", "r", stdin);
#endif
ios::sync_with_stdio(0),cin.tie(0);
cin >> n;
for (int i = 1;i <= n;i++)
cin >> a[i];
sort(a+1,a+1+n);
reverse(a+1,a+1+n);
for (int i = 1;i <= n;i++)
if (!is(a[i])){
cout <<a[i]<<endl;
return 0;
}
return 0;
}
【Codecraft-18 and Codeforces Round #458 (Div. 1 + Div. 2, combined) A】 Perfect Squares的更多相关文章
- Educational Codeforces Round 60 (Rated for Div. 2) - D. Magic Gems(动态规划+矩阵快速幂)
Problem Educational Codeforces Round 60 (Rated for Div. 2) - D. Magic Gems Time Limit: 3000 mSec P ...
- Educational Codeforces Round 71 (Rated for Div. 2)-F. Remainder Problem-技巧分块
Educational Codeforces Round 71 (Rated for Div. 2)-F. Remainder Problem-技巧分块 [Problem Description] ...
- Educational Codeforces Round 71 (Rated for Div. 2)-E. XOR Guessing-交互题
Educational Codeforces Round 71 (Rated for Div. 2)-E. XOR Guessing-交互题 [Problem Description] 总共两次询 ...
- Educational Codeforces Round 72 (Rated for Div. 2)-D. Coloring Edges-拓扑排序
Educational Codeforces Round 72 (Rated for Div. 2)-D. Coloring Edges-拓扑排序 [Problem Description] 给你 ...
- Educational Codeforces Round 60 (Rated for Div. 2) - C. Magic Ship
Problem Educational Codeforces Round 60 (Rated for Div. 2) - C. Magic Ship Time Limit: 2000 mSec P ...
- Educational Codeforces Round 43 (Rated for Div. 2)
Educational Codeforces Round 43 (Rated for Div. 2) https://codeforces.com/contest/976 A #include< ...
- Educational Codeforces Round 35 (Rated for Div. 2)
Educational Codeforces Round 35 (Rated for Div. 2) https://codeforces.com/contest/911 A 模拟 #include& ...
- Codeforces Educational Codeforces Round 44 (Rated for Div. 2) F. Isomorphic Strings
Codeforces Educational Codeforces Round 44 (Rated for Div. 2) F. Isomorphic Strings 题目连接: http://cod ...
- Codeforces Educational Codeforces Round 44 (Rated for Div. 2) E. Pencils and Boxes
Codeforces Educational Codeforces Round 44 (Rated for Div. 2) E. Pencils and Boxes 题目连接: http://code ...
随机推荐
- linux下python3源码安装及卸载
Linux下Python3的源码编译安装和卸载方法 [日期:2019-06-21] 来源:博客园 作者:wuli潇萧 [字体:大 中 小] (一)Linux下软件的源码编译安装和卸载方法 L ...
- iOS开发——捕获崩溃信息
可通过注册NSUncaughtExceptionHandler捕获异常信息,将拿到的NSException细节写入Crash日志,精准的定位出错程序位置,有需要的,可直接将crash信息直接上传服务器 ...
- 说说Kindle那些事
已经不记得是什么时候在哪里听过kindle这玩意的了,反正最开始买kindle还是大四上学期,貌似是2012-9-30,那时候是整个大学最闲的时候,不知道哪天闲的蛋疼一冲动就买了个kindle4黑色款 ...
- 【uva 1025】A Spy in the Metro
[题目链接]:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_probl ...
- iBatis框架使用 4步曲
iBatis是一款使用方便的数据訪问工具,也可作为数据持久层的框架.和ORM框架(如Hibernate)将数据库表直接映射为Java对象相比.iBatis是将SQL语句映射为Java对象. 相对于全自 ...
- Oracle 复制随意表一行的SQL语句(測试Ok)
測试了非常久,网上说的方法非常多,事实上都是错误的.正确的写法: declare cursor rowAll is select * from tb_news where 1=1; row1 tb_n ...
- oracle job有定时执行功能
oracle job有定时执行的功能,可以在指定的时间点或每天的某个时间点自行执行任务. oracle job有定时执行的功能,可以在指定的时间点或每天的某个时间点自行执行任务. 一.查询系统中的 ...
- BZOJ 1055 DP
思路: f[i][j][k]表示i到j匹配了字母k if(m,n能匹配上k) f[i][j][k]|=f[i][l][m]&f[l+1][j][n] 一个大枚举 就OK了~ //By Siri ...
- Postfix邮件系统安装配置视频
Postfix邮件系统安装配置视频(文字资料详见linux企业应用案例精解),全部视频分为四个部分,详情如下: http://115.com/file/be9j4dsj#postfix-1.rar h ...
- Debian9 ifconfig命令找不到解决办法
Debian9 ifconfig命令找不到解决办法 ifconfig.route.arp和netstat等命令行工具(它们统称为net-tools),管理和排查各种网络配置.这类工具原先起源于BSD ...