Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.

Example 1:

Input: "Let's take LeetCode contest"
Output: "s'teL ekat edoCteeL tsetnoc"

Note: In the string, each word is separated by single space and there will not be any extra space in the string.

151. Reverse Words in a String186. Reverse Words in a String II 的类似题目,这题是让翻转字符串里的单词。

Python:One Place

class Solution(object):
def reverseWords(self, s): def reverse(s, begin, end):
for i in xrange((end - begin) // 2):
s[begin + i], s[end - 1 - i] = s[end - 1 - i], s[begin + i] s, i = list(s), 0
for j in xrange(len(s) + 1):
if j == len(s) or s[j] == ' ':
reverse(s, i, j)
i = j + 1
return "".join(s)

Python:New Array

class Solution2(object):
def reverseWords(self, s):
reversed_words = [word[::-1] for word in s.split(' ')]
return ' '.join(reversed_words)

C++:

class Solution {
public:
string reverseWords(string s) {
for (int i = 0, j = 0; j <= s.length(); ++j) {
if (j == s.length() || s[j] == ' ') {
reverse(s.begin() + i, s.begin() + j);
i = j + 1;
}
}
return s;
}
};

     

类似题目:

[LeetCode] 151. Reverse Words in a String 翻转字符串中的单词

[LeetCode] 186. Reverse Words in a String II 翻转字符串中的单词 II

All LeetCode Questions List 题目汇总

[LeetCode] 557. Reverse Words in a String III 翻转字符串中的单词 III的更多相关文章

  1. [LeetCode] 186. Reverse Words in a String II 翻转字符串中的单词 II

    Given an input string, reverse the string word by word. A word is defined as a sequence of non-space ...

  2. [LeetCode] Reverse Words in a String II 翻转字符串中的单词之二

    Given an input string, reverse the string word by word. A word is defined as a sequence of non-space ...

  3. LeetCode刷题:Reverse Words in a String(翻转字符串中的单词)

    题目 Given an input string, reverse the string word by word. For example, Given s = "the sky is b ...

  4. [LeetCode] Reverse Words in a String III 翻转字符串中的单词之三

    Given a string, you need to reverse the order of characters in each word within a sentence while sti ...

  5. LeetCode 557. Reverse Words in a String III (反转字符串中的单词 III)

    Given a string, you need to reverse the order of characters in each word within a sentence while sti ...

  6. [LeetCode] 151. Reverse Words in a String 翻转字符串中的单词

    Given an input string, reverse the string word by word. For example,Given s = "the sky is blue& ...

  7. Leetcode#557. Reverse Words in a String III(反转字符串中的单词 III)

    题目描述 给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序. 示例 1: 输入: "Let's take LeetCode contest" 输 ...

  8. C#版(击败97.76%的提交) - Leetcode 557. 反转字符串中的单词 III - 题解

    版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. Leetcod ...

  9. Java实现 LeetCode 557 反转字符串中的单词 III(StringBuilder的翻转和分割)

    557. 反转字符串中的单词 III 给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序. 示例 1: 输入: "Let's take LeetCode c ...

随机推荐

  1. LGOJP1850 换教室

    题目地址 https://www.luogu.org/problem/P1850 题解 这题的转移其实挺好想的但是方程特别长...真的特别长... 首先设\(f[i,j,0/1]\)表示当前在第\(i ...

  2. 与你一起学习MS Project——高级篇:Project高级应用

    我们再来看Project的一些高级应用. 一.设置任务依赖性的几种方法 首先是设置任务依赖性的几种方法,这里介绍三种方法. 方法一:选中两个需要建立依赖型的任务.选中用 ctrl 鼠标左键 的方式即可 ...

  3. 手写队列以及stl中队列的使用

    一,手写队列. struct queue { ; ,rear=,a[maxn]; void push(int x) { a[++rear]=x; } void pop() { first++; } i ...

  4. solidworks 学习 (一)

    螺丝刀建模

  5. MySQL 已有大数据量表进行分区踩坑

    一.背景mysql 表中已有 4 亿数据,为提高查询效率,需创建分区,一开始计划是创建 HASH 分区,结果报错:ERROR 1659 (HY000): Field 'partno' is of a ...

  6. Don't rely on luck.

    https://www.codewars.com/kata/dont-rely-on-luck/train/javascript 答案: 重写 Math.floor = function () ... ...

  7. C# list常用的几个操作 改变list中某个元素的值 替换某一段数据

    1.改变list中某个元素的值 public class tb_SensorRecordModel { public int ID { get; set; } public decimal Value ...

  8. [golang]Golang实现高并发的调度模型---MPG模式

    Golang实现高并发的调度模型---MPG模式 传统的并发形式:多线程共享内存,这也是Java.C#或者C++等语言中的多线程开发的常规方法,其实golang语言也支持这种传统模式,另外一种是Go语 ...

  9. MATLAB 线性规划实例应用

    线性规划 线性规划函数 功能:求解线性规划问题 语法 x = linprog(f,A,b):求解问题 min fx,约束条件为 Ax <= b x = linprog(f,A,b,Aeq,beq ...

  10. mysql upper() 函数

    mysql> select upper(" cdcdcd"); +------------------+ | upper(" cdcdcd") | +-- ...