URAL(timus) 1280 Topological Sorting(模拟)

Topological Sorting

Time limit: 1.0 second
Memory limit: 64 MB

Michael wants to win the world championship in programming and decided to study N subjects (for convenience we will number these subjects from 1 to N).
Michael has worked out a study plan for this purpose. But it turned out
that certain subjects may be studied only after others. So, Michael’s
coach analyzed all subjects and prepared a list of M limitations in the form “s_i u_i” (1 ≤ s_i, u_i ≤ N; i = 1, 2, …, M), which means that subject s_i must be studied before subject u_i.

Your task is to verify if the order of subjects being studied is correct.

Remark.
It may appear that it’s impossible to find the correct order of
subjects within the given limitations. In this case any subject order
worked out by Michael is incorrect.

Limitations
1 ≤ N ≤ 1000; 0 ≤ M ≤ 100000.

Input

The first line contains two integers N and M (N is the number of the subjects, M is the number of the limitations). The next M lines contain pairs s_i, u_i, which describe the order of subjects: subject s_i must be studied before u_i. Further there is a sequence of N unique numbers ranging from 1 to N — the proposed study plan.

Output

Output
a single word “YES” or “NO”. “YES” means that the proposed order is
correct and has no contradictions with the given limitations. “NO” means
that the order is incorrect.

Samples

input	output
5 6 1 3 1 4 3 5 5 2 4 2 1 2 1 3 4 5 2	YES
5 6 1 3 1 4 3 5 5 2 4 2 1 2 1 2 4 5 3	NO

#include <iostream>
#include <cstring>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <time.h>
#include <string>
#include <map>
#include <stack>
#include <vector>
#include <set>
#include <queue>
#define inf 10000000
#define mod 10000
typedef long long ll;
using namespace std;
const int N=;
const int M=;
int power(int a,int b,int c){int ans=;while(b){if(b%==){ans=(ans*a)%c;b--;}b/=;a=a*a%c;}return ans;}
int in[N],vis[N],w[N][N];
int n,m,k;
vector<int>vec[N];

int main()
{
    int a,b;
    bool flag=true;
    scanf("%d%d",&n,&m);
    while(m--){
        scanf("%d%d",&a,&b);
        if(!w[a][b]){
            w[a][b]=;
            vec[a].push_back(b);
        }
    }
    for(int i=;i<=n;i++){
        scanf("%d",&in[i]);
    }
    for(int i=;i<=n;i++){
        int cnt=;
        for(int j=i+;j<=n;j++){
            if(w[in[i]][in[j]])cnt++;
        }
    if(cnt!=vec[in[i]].size())flag=false;

    }
    if(flag)printf("YES\n");
    else printf("NO\n");
    return ;
}