POJ 2359 Questions
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 1228 | Accepted: 449 |
Description
The jury of the Third Urals Collegiate Programming Contest being clever enough has found a simple way to make its work easier. We have invented a simple algorithm that will help us answer ALL your numerous questions! Moreover, this algorithm guarantees that the same questions will have the same answers (this would be hardly possible, if we would undertook such a task ourselves). According to this algorithm a member of the jury starts to delete characters of the question in the following order:
- Starting from the first character he or she counts out N-1 characters (spaces, punctuation marks etc. are considered to be characters too) and deletes the Nth character.
- If a string ends the count continues from the beginning of the string.
- After deleting a character the count restarts from the character that would be the (N+1)-st in the previous count.
- If the last remaining character is a question-mark ("?") then the answer to the question is "Yes". If it is a space then the answer is "No". Any other character will lead to "No comments" answer.
You should help the jury and write a program that will do a hard work of answering your questions tomorrow. The number N is secret and will not be announced even after the end of the contest. Your program should use N=1999.
For example, taking a string "Is it a good question?" (its length is 22) the characters will be counted in the following way: "Is it a good question?Is it ... quest" and "i" will be deleted. Then the count restarts from "on?Is it..." etc., until "s" will be left (thus the answer is "No comments", as usual).
Input
The size of the input file is not more than 30000.
Output
Sample Input
Sample input #1
Does the jury of this programming contest use the
algorithm described in this problem to answer my questions? Sample input #2
At least, will anybody READ my question? Sample input #3
This is
UNFAIR!
Sample Output
Sample output #1
Yes Sample output #2
No Sample output #3
No comments
解题方法:约瑟夫问题,直接套用递推公式。
#include <stdio.h>
#include <string.h>
#include <iostream>
using namespace std; char temp[]; int main()
{
string str;
int n = ;
int ans = ;
while(gets(temp))
{
str += temp;
}
int nLen = str.length();
for (int i = ; i <= nLen; i++)
{
ans = (ans + n) % i;
}
if (str[ans] == '?')
{
printf("Yes\n");
}
else
{
if (str[ans] == ' ')
{
printf("No\n");
}
else
{
printf("No comments\n");
}
}
return ;
}
POJ 2359 Questions的更多相关文章
- POJ 2359 Questions(约瑟夫环——数学解法)
题目链接: http://poj.org/problem?id=2359 题意描述: 输入一个字符串 按照下面的规则,如果剩下的最后一个字符是'?',输出"Yes",如果剩下的最后 ...
- Poj 2371 Questions and answers(排序)
题目链接:http://poj.org/problem?id=2371 思路分析:使用计数排序或其他时间复杂度为O( log N )的排序. 代码如下: #include <iostream&g ...
- [划分树] POJ 2104 K-th Number
K-th Number Time Limit: 20000MS Memory Limit: 65536K Total Submissions: 51732 Accepted: 17722 Ca ...
- POJ 题目分类(转载)
Log 2016-3-21 网上找的POJ分类,来源已经不清楚了.百度能百度到一大把.贴一份在博客上,鞭策自己刷题,不能偷懒!! 初期: 一.基本算法: (1)枚举. (poj1753,poj2965 ...
- (转)POJ题目分类
初期:一.基本算法: (1)枚举. (poj1753,poj2965) (2)贪心(poj1328,poj2109,poj2586) (3)递归和分治法. (4)递推. ...
- poj分类
初期: 一.基本算法: (1)枚举. (poj1753,poj2965) (2)贪心(poj1328,poj2109,poj2586) (3)递归和分治法. ( ...
- 类似区间计数的种类并查集两题--HDU 3038 & POJ 1733
1.POJ 1733 Parity game Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 5744 Accepted: ...
- 【POJ】2104 K-th Number(区间k大+主席树)
http://poj.org/problem?id=2104 裸题不说.主席树水过. #include <cstdio> #include <iostream> #includ ...
- POJ 2104&HDU 2665 Kth number(主席树入门+离散化)
K-th Number Time Limit: 20000MS Memory Limit: 65536K Total Submissions: 50247 Accepted: 17101 Ca ...
随机推荐
- jQuery选择器之样式二
prop()方法和attr()类似,但是HTML5规定有一种属性在DOM节点中可以没有值,只有出现与不出现两种,例如: <input id="test-radio" type ...
- Android自定义view之仿微信录制视频按钮
本文章只写了个类似微信的录制视频的按钮,效果图如下: 一.主要的功能: 1.长按显示进度条,单击事件,录制完成回调 2.最大时间和最小时间控制 3.进度条宽度,颜色设置 二.实 ...
- mysqlsla安装和使用介绍
安装mysqlsla源码路径:https://github.com/daniel-nichter/hackmysql.com源码存放路径:/usr/local/src1.获取源码如果没有git命令,请 ...
- SQLServer同一实例下事务操作
参考代码: 引用Dapper public bool OrderAdd2(User user, Order order) { string dbString = ConfigurationManage ...
- 洛谷 P2419 [USACO08JAN]牛大赛Cow Contest
题目背景 [Usaco2008 Jan] 题目描述 N (1 ≤ N ≤ 100) cows, conveniently numbered 1..N, are participating in a p ...
- 2010: C语言实验——逆置正整数
2010: C语言实验——逆置正整数 Time Limit: 1 Sec Memory Limit: 64 MBSubmit: 949 Solved: 691[Submit][Status][We ...
- noj-1102-黑白图像
1 //题目地址:http://acm.njupt.edu.cn/acmhome/problemdetail.do?method=showdetail&id=1102 ...
- Springboot 命令注入属性[--]&[-D]
场景 在用Jenkins,做自动化部署时,遇到一些命令问题. 需要通过命令的形式,注入些业务值. -D 系统属性注入 Java,启动jar 命令: java [ options ] -jar file ...
- MAC环境Android SDK环境变量配置
一.材料 1.Mac设备1台: 2.下载并更新android SDK:示列中sdk存放路径为/Users/gametest/Library/Android/sdk 二.操作步骤 1.启动Termina ...
- iCheck获取单选和复选框的值和文本
//获取单选和复选框的值//parameters.type:"radio","checkbox"//parameters.name:input-name//pa ...