I:trainage Ditches
总时间限制: 1000ms 内存限制: 65536kB
描述
Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water for awhile and takes quite a long time to regrow. Thus, Farmer John has built a set of drainage ditches so that Bessie's clover patch is never covered in water. Instead, the water is drained to a nearby stream. Being an ace engineer, Farmer John has also installed regulators at the beginning of each ditch, so he can control at what rate water flows into that ditch.
Farmer John knows not only how many gallons of water each ditch can transport per minute but also the exact layout of the ditches, which feed out of the pond and into each other and stream in a potentially complex network.
Given all this information, determine the maximum rate at which water can be transported out of the pond and into the stream. For any given ditch, water flows in only one direction, but there might be a way that water can flow in a circle.
输入
The input includes several cases. For each case, the first line contains two space-separated integers, N (0 <= N <= 200) and M (2 <= M <= 200). N is the number of ditches that Farmer John has dug. M is the number of intersections points for those ditches. Intersection 1 is the pond. Intersection point M is the stream. Each of the following N lines contains three integers, Si, Ei, and Ci. Si and Ei (1 <= Si, Ei <= M) designate the intersections between which this ditch flows. Water will flow through this ditch from Si to Ei. Ci (0 <= Ci <= 10,000,000) is the maximum rate at which water will flow through the ditch.
输出
For each case, output a single integer, the maximum rate at which water may emptied from the pond.
样例输入
5 4
1 2 40
1 4 20
2 4 20
2 3 30
3 4 10
样例输出
50
I:trainage Ditches的更多相关文章
- POJ 1273 Drainage Ditches题解——S.B.S.
Drainage Ditches Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 67823 Accepted: 2620 ...
- POJ1273Drainage Ditches[最大流]
Drainage Ditches Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 71559 Accepted: 2784 ...
- poj1273 Drainage Ditches
Drainage Ditches Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 68414 Accepted: 2648 ...
- POJ 1273 Drainage Ditches
Drainage Ditches Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 67387 Accepted: 2603 ...
- HDU1532 Drainage Ditches 网络流EK算法
Drainage Ditches Problem Description Every time it rains on Farmer John's fields, a pond forms over ...
- POJ-1273 Drainage Ditches 最大流Dinic
Drainage Ditches Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 65146 Accepted: 25112 De ...
- POJ 1273 Drainage Ditches -dinic
dinic版本 感觉dinic算法好帅,比Edmonds-Karp算法不知高到哪里去了 Description Every time it rains on Farmer John's fields, ...
- HD1532Drainage Ditches(最大流模板裸题 + 邻接表)
Drainage Ditches Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) ...
- Drainage Ditches(dinic)
Drainage Ditches Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 59210 Accepted: 2273 ...
随机推荐
- DLL库
6.阿里云上传.下载:Aliyun.OSS.dll https://help.aliyun.com/ 5.SQLite数据库操作:SQLite.Interop.dll.SQLite.Designer. ...
- Mybatis select返回值为map时,选取表字段的两列作为key,value
项目需要从ibatis升级到MyBatis,dao中有一个方法返回Map类型,具体是查询语句查询两个字段,将结果列表字段A的值作为key字段B的值作为value存入Map中作为结果返回: ibatis ...
- sqllite 默认当前日期写法
create table IF NOT EXISTS realpoint(_id integer primary key autoincrement,rountId varchar(50),lng d ...
- wps使用技巧
1.和word一样的文档结构图: 视图->文档结构图 (不是导航窗格) 2.粘贴时,出现乱码: WPS->选项->默认粘贴方式:无格式文本. 3.浏览当前文档所在目录: 在WPS的标 ...
- IOS 创建渐变图层
代码如下 typedef enum { GradientLayerKindLeftRight = , GradientLayerKindUpDown, GradientLayerKindLBRT,// ...
- 关于iOS 10不能跳转设置的解决办法
NSURL*url=[NSURL URLWithString:@"Prefs:root=WIFI"]; Class LSApplicationWorkspace = NSClas ...
- 新项目CRM(1)
<title>CRM登陆</title> <script type="text/javascript"> if (window.parent.w ...
- 前端 JS POST提交
/*点击事件*/ function deleteExportItemAndEportUser(id) { post("deleteExportItemAndEportUser" ...
- <转>好婚姻是彼此放心
-01- 临下班,马丽听到隔壁桌的方雅在打电话,声音听起来嗲声嗲气:“有个朋友晚上约我吃饭,要晚点回来,你不用等我了哦.” 电话挂断时,已经到了下班的点.方雅扭头对马丽说:“丽姐,待会我们一起去吃个饭 ...
- 剑指offer四:链表中倒数第k个结点
输入一个链表,输出该链表中倒数第K个结点 public class ListNode { int val; ListNode next = null; ListNode(int val) { this ...