注意点:

  1. 最后的进位
  2. (l1 == null || l1.next == null)
  3. break;
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
boolean j = false;
ListNode p = new ListNode(0);
ListNode res = p;
while(true){
int a = (l1 != null ? l1.val : 0) + (l2 != null ? l2.val : 0) + (j ? 1 : 0);
if(a >= 10){
j = true;
p.val = a - 10;
}else{
j = false;
p.val = a;
} l1 = (l1 == null || l1.next == null) ? null : l1.next;
l2 = (l2 == null || l2.next == null) ? null : l2.next;
boolean ok = l1 == null && l2 == null;
if(! ok){
p.next = new ListNode(0);
p = p.next;
}else
break;
}
if(j)
p.next = new ListNode(1);
return res;
}

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