C#中使用like和in参数传值

like 参数：

string strSql = "select * from Person.Address where City like '%'+ @add + '%'";
SqlParameter[] Parameters=new SqlParameter[];
Parameters[] = new SqlParameter("@add", "bre");

in 参数：

public bool AssignToAnotherRoleBatch(List<int> idList, int newRoleId,string newRoleName, int newWorkerId, string newWorkerName, out string msg)
        {
            msg = "";
            string[] ids = Array.ConvertAll<int, string>(idList.ToArray(), a => a.ToString());
            string idstr = string.Join(",", ids);
            idstr = "," + idstr + ",";
            try
            {
                string sql = "update Customers set RoleId=@roleId,RoleName=@roleName,WorkerId=@workerId,WorkerName=@workerName where charindex(','+rtrim(Id) + ',' ,@idList)>0";

                var cmd = new SqlCommand(sql, tradeConnection);
                cmd.Parameters.AddWithValue("@roleId", newRoleId);
                cmd.Parameters.AddWithValue("@roleName", newRoleName);
                cmd.Parameters.AddWithValue("@workerId", newWorkerId);
                cmd.Parameters.AddWithValue("@workerName", newWorkerName);
                cmd.Parameters.AddWithValue("@idList", idstr);
                int count = cmd.ExecuteNonQuery();
                if (count > )
                    return true;
            }
            catch( Exception e)
            {
                LogHelper.Err(e.Message+e.StackTrace);
                msg = e.Message;
            }
            return false;
        }

另外的使用in 参数的方法，@Role赋值 '1,2,3,4'，如下：

exec("SELECT * FROM sys_User WHERE RoleID in ('" + @RoleID + "')")