【BZOJ】1699 [Usaco2007 Jan]Balanced Lineup排队

【算法】线段树

#include<cstdio>
#include<cctype>
#include<algorithm>
using namespace std;
const int inf=0x3f3f3f3f,maxn=;
struct tree{int l,r,mins,maxs;}t[maxn*];
int n,q,a[maxn];
int read_t;char c;
int read()
{
    read_t=;
    while(!isdigit(c=getchar()));
    do{read_t=read_t*+c-'';}while(isdigit(c=getchar()));
    return read_t;
}
void build(int k,int l,int r)
{
    t[k].l=l;t[k].r=r;
    if(l==r)t[k].mins=a[l],t[k].maxs=a[r];
     else
      {
          int mid=(l+r)>>;
          build(k<<,l,mid);
          build(k<<|,mid+,r);
          t[k].mins=min(t[k<<].mins,t[k<<|].mins);
          t[k].maxs=max(t[k<<].maxs,t[k<<|].maxs);
      }
}
int askmaxs(int k,int l,int r)
{
    int left=t[k].l,right=t[k].r;
    if(l<=left&&r>=right)return t[k].maxs;
     else
      {
          int mid=(left+right)>>,ans=;
          if(l<=mid)ans=askmaxs(k<<,l,r);
          if(r>mid)ans=max(ans,askmaxs(k<<|,l,r));
          return ans;
      }
}
int askmins(int k,int l,int r)
{
    int left=t[k].l,right=t[k].r;
    if(l<=left&&r>=right)return t[k].mins;
     else
      {
          int mid=(left+right)>>,ans=inf;
          if(l<=mid)ans=askmins(k<<,l,r);
          if(r>mid)ans=min(ans,askmins(k<<|,l,r));
          return ans;
      }
}
int main()
{
    n=read();q=read();
    for(int i=;i<=n;i++)a[i]=read();
    build(,,n);
    for(int i=;i<=q;i++)
     {
         int u=read(),v=read();
         printf("%d\n",askmaxs(,u,v)-askmins(,u,v));
     }
    return ;
}