Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.

+---------+------------------+------------------+
| Id(INT) | RecordDate(DATE) | Temperature(INT) |
+---------+------------------+------------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+---------+------------------+------------------+

For example, return the following Ids for the above Weather table:

+----+
| Id |
+----+
| 2 |
| 4 |
+----+

Code

SELECT w1.Id FROM Weather AS w1, Weather AS w2 WHERE w1.Temperature > w2.Temperature AND dateDiff(w2.RecordDate, w1.RecordDate) = -1

or

SELECT w1.Id FROM Weather AS w1, Weather AS w2 WHERE w1.Temperature > w2.Temperature AND dateDiff(w1.RecordDate, w2.RecordDate) = 1

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