[LeetCode&Python] Problem 599. Minimum Index Sum of Two Lists
Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.
You need to help them find out their common interest with the least list index sum. If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.
Example 1:
Input:
["Shogun", "Tapioca Express", "Burger King", "KFC"]
["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"]
Output: ["Shogun"]
Explanation: The only restaurant they both like is "Shogun".
Example 2:
Input:
["Shogun", "Tapioca Express", "Burger King", "KFC"]
["KFC", "Shogun", "Burger King"]
Output: ["Shogun"]
Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).
Note:
- The length of both lists will be in the range of [1, 1000].
- The length of strings in both lists will be in the range of [1, 30].
- The index is starting from 0 to the list length minus 1.
- No duplicates in both lists.
class Solution(object):
def findRestaurant(self, list1, list2):
"""
:type list1: List[str]
:type list2: List[str]
:rtype: List[str]
"""
ans=[]
ma=100000
n=len(list1)
for i in range(n):
s=list1[i]
if s in list2:
j=list2.index(s)
if i+j<=ma:
ma=i+j
ans.append(s)
return ans
[LeetCode&Python] Problem 599. Minimum Index Sum of Two Lists的更多相关文章
- 【Leetcode_easy】599. Minimum Index Sum of Two Lists
problem 599. Minimum Index Sum of Two Lists 题意:给出两个字符串数组,找到坐标位置之和最小的相同的字符串. 计算两个的坐标之和,如果与最小坐标和sum相同, ...
- 【LeetCode】599. Minimum Index Sum of Two Lists 解题报告(Python)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:找到公共元素再求索引和 方法二:索引求和,使 ...
- LeetCode 599. Minimum Index Sum of Two Lists (从两个lists里找到相同的并且位置总和最靠前的)
Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite ...
- 599. Minimum Index Sum of Two Lists
Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite ...
- 599. Minimum Index Sum of Two Lists(easy)
Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite ...
- 599. Minimum Index Sum of Two Lists两个餐厅列表的索引和最小
[抄题]: Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of fa ...
- LC 599. Minimum Index Sum of Two Lists
题目描述 Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of fav ...
- LeetCode 599: 两个列表的最小索引总和 Minimum Index Sum of Two Lists
题目: 假设 Andy 和 Doris 想在晚餐时选择一家餐厅,并且他们都有一个表示最喜爱餐厅的列表,每个餐厅的名字用字符串表示. Suppose Andy and Doris want to cho ...
- [LeetCode] Minimum Index Sum of Two Lists 两个表单的最小坐标和
Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite ...
随机推荐
- Oracle12c中配置实例参数和修改容器数据库(CDB)及可插拔数据库(PDB)
Oracle12c中的多宿主选项允许一个容器数据库(CDB)容纳多个独立的可插拔数据库(PDB).本文将展示如何配置实例参数和修改容器数据库(CDB)及可插拔数据库(PDB).1. 配置CDB中的实例 ...
- Django信息安全相关之CSRF和XSS
什么是xss攻击 xss攻击:黑客把恶意的JS脚本提交到后端,后端把恶意脚本渲染显示出来 什么是CSRF? 1.你登录建行官网后 你的浏览器就保存了建行网站的cokie,(如果不关闭这个页面c ...
- nyoj 0325 zb的生日(dp)
nyoj 0325 zb的生日 zb的生日 时间限制:3000 ms | 内存限制:65535 KB 难度:2 描述 今天是阴历七月初五,acm队员zb的生日.zb正在和C小加.never在武汉集 ...
- LY.JAVA.DAY12.String类
2018-07-24 14:06:03 String类概述 字符串是由多个字符组成一串数据(字符序列) 字符串可以看成字符数组 一旦被赋值就不能被改变 值不能变 1.过程概述: 方法区---字符 ...
- @ResponseBody中文乱码解决方案
java web项目,使用了springmvc4.0,用@ResponseBody返回中文字符串,乱码$$ 本以为很简单的问题,不过也找了一个小时. 网上有说这样配置的: <mvc:annota ...
- oo作业总结(二)
概述 和前三次作业相比,这几次作业最大的不同是难度的飞跃.遗憾的是在这难度的变化面前,我自己却没有做好充分的准备,错误的低估了作业难度导致给自己带来了很多不必要麻烦和损失.接下来我将对它们进行说明(度 ...
- CSS(二)属性--文本设置
HTML代码一 <body> <div>这是一个很黑很黑的夜晚,黑云密布,没有任何光亮透过.卖火柴的小姑娘.......</div> </body> C ...
- RegDataToDataType
function RegDataToDataType(Value: TRegDataType): Integer; begin case Value of rdString: Result := RE ...
- 给msde加装企业管理器
-=给msde加装企业管理器=- 首先,反对所谓的绿色版,运行那是 相~~~当 不稳定,自动关闭,要你有什么用?还广告飞扬!为了调试,花了我整整一天的时间.给大家节省的时间,也为了让大家少走点弯路. ...
- day24 模块03_re
休养生息 --模块03 1.正则表达式 2.在python中使用正则.re 一,正则表达式 (匹配字符串,主要是给字符串使用的) 1)元字符 . 除换行符之外 \w 数字,字母,下划线组成 \W ...