281. Zigzag Iterator
题目:
Given two 1d vectors, implement an iterator to return their elements alternately.
For example, given two 1d vectors:
v1 = [1, 2]
v2 = [3, 4, 5, 6]
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1, 3, 2, 4, 5, 6].
Follow up: What if you are given k 1d vectors? How well can your code be extended to such cases?
Clarification for the follow up question - Update (2015-09-18):
The "Zigzag" order is not clearly defined and is ambiguous for k > 2 cases. If "Zigzag" does not look right to you, replace "Zigzag" with "Cyclic". For example, given the following input:
[1,2,3]
[4,5,6,7]
[8,9]
It should return [1,4,8,2,5,9,3,6,7].
链接: http://leetcode.com/problems/zigzag-iterator/
题解:
Zigzag Iterator。最简单的就是用两个index分别遍历两个list,然后用一个boolean变量来控制何时遍历哪一个list。 好像我这么做是有问题的,应该用Interator<>来做。
Time Complexity - O(n), Space Complexity - O(1)
public class ZigzagIterator {
private int length;
private int index1 = 0;
private int index2 = 0;
private List<Integer> list1;
private List<Integer> list2;
private boolean useList2;
public ZigzagIterator(List<Integer> v1, List<Integer> v2) {
this.length = v1.size() + v2.size();
list1 = v1;
list2 = v2;
if(list1.size() == 0) {
useList2 = true;
}
}
public int next() {
if(!useList2) {
if(index2 < list2.size()) {
useList2 = true;
}
return list1.get(index1++);
} else {
if(index1 < list1.size()) {
useList2 = false;
}
return list2.get(index2++);
}
}
public boolean hasNext() {
return (index1 + index2) < length;
}
}
/**
* Your ZigzagIterator object will be instantiated and called as such:
* ZigzagIterator i = new ZigzagIterator(v1, v2);
* while (i.hasNext()) v[f()] = i.next();
*/
Reference:
https://leetcode.com/discuss/57961/o-n-time-%26-o-1-space-java-solution
https://leetcode.com/discuss/63037/simple-java-solution-for-k-vector
https://leetcode.com/discuss/58012/short-java-o-1-space
https://leetcode.com/discuss/71857/clean-java-solution-works-for-k-lists
281. Zigzag Iterator的更多相关文章
- [LeetCode] 281. Zigzag Iterator 之字形迭代器
Given two 1d vectors, implement an iterator to return their elements alternately. Example: Input: v1 ...
- [LeetCode#281] Zigzag Iterator
Problem: Given two 1d vectors, implement an iterator to return their elements alternately. For examp ...
- 281. Zigzag Iterator z字型遍历
[抄题]: Given two 1d vectors, implement an iterator to return their elements alternately. Example: Inp ...
- 【LeetCode】281. Zigzag Iterator 解题报告 (C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 deque 日期 题目地址:https://leetc ...
- [Locked] Zigzag Iterator
Zigzag Iterator Given two 1d vectors, implement an iterator to return their elements alternately. Fo ...
- Zigzag Iterator II
Description Follow up Zigzag Iterator: What if you are given k 1d vectors? How well can your code be ...
- [LeetCode] Zigzag Iterator 之字形迭代器
Given two 1d vectors, implement an iterator to return their elements alternately. For example, given ...
- Zigzag Iterator
Given two 1d vectors, implement an iterator to return their elements alternately. For example, given ...
- LeetCode Zigzag Iterator
原题链接在这里:https://leetcode.com/problems/zigzag-iterator/ 题目: Given two 1d vectors, implement an iterat ...
随机推荐
- c++实例化对象
今天看到c++实例化对象,有点懵了.Activity_Log the_log (theLogPtr, Tree->GetBranch());这是那一段小代码,开始没看懂.java看习惯了总喜欢n ...
- 格式化输出[parts/iomanip]
/* 用ios类中的成员函数来进行IO格式的控制总需要写一条单独的语句,而不能直接嵌入到IO语句中,显得很不方便,因此C++又提供了一种用操作符来控制IO的格式.操作符分为带参和不带参两种,带参的定义 ...
- xml基础学习笔记03
继续上篇xml学习笔记,坚持.坚持.再坚持啊.... 本篇主要记录: 35.XML节点的删除与修改 36集.用XML制作RSS订阅源 <?php /* 笔记: 35.XML节点的删除与修改 使用 ...
- 查看python selenium的api
打开命令行工具,doc中输入: python -m pydoc -p 然后在浏览器中访问http://localhost:4567/,此时应该可以看到python中所有的Modules 按ctrl+f ...
- Reveal 破解
永久试用Reveal,只需要打开 ~/Library/Preferences/com.ittybittyapps.Reveal.plist 把IBAApplicationPersistenceData ...
- vmware workstation 10.0
2013.9.3 vmware workstation 10.0 build 1295980新增功能– 可以将windows 8.1物理pc转变为虚拟机:unity模式增强,与windows 8.1 ...
- bzoj 2327 构图暴力判断+独立集个数
首先我们可以处理出10^6以内的所有的勾股数,如果我们有2*i-1和2*j互质, 那么A=(2*i-1)*(2*i-1)+(2*i-1)*(2*j),B=2*j*j+(2*i-1)*(2*j)为互质 ...
- C++ Template之函数模版
函数模版的定义: template <typename T> T const& max(const T& a,const T b) { return a > b ? ...
- 【转载】让c++ 函数返回一个数组
在c++中是不允许数组作为函数的返回值的 int [] someFunction( ); //ILLEGAL 要想实现函数返回一个数组,那返回对应数组里面类型的指针 you must return a ...
- NGP处理包
NGP处理部分(主要就是这个RunOnce函数,客户单肯定是开个线程取调用这个RunOnce的) void NGP::RunOnce() { m_spTimerFac->driveTimer() ...